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Ilya [14]
3 years ago
15

5x-2y=3 -5x+4y=9 Solve the system of equations

Mathematics
1 answer:
german3 years ago
3 0

the answer to this system of linear equations is (3,6)

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The graph of y=f(x) is above. If f(−4)=k, what is the value of f(k)?
cupoosta [38]

Answer:

B

The answer is B, which is -1.5.

3 0
3 years ago
Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile dr
stiv31 [10]

The given question is incomplete. The complete question is:

Omar rented a truck for one day. There was a base fee of $17.95, and there was an additional charge of 98 cents for each mile driven. Omar had to pay $23 when he returned the truck. For how many mile did he drive the truck?

Answer: Omar drove the truck for 5.15 miles

Step-by-step explanation:

Base fee = 17.95 $

Additional charge per mile = 98 cents = 0.98 $     ( 100cents = 1$)

Now Omar payed = 22 $

Let the miles he travelled = x

Now , 17.95+0.98\times x=23

Solvimg for x :

x=5.15miles

Thus Omar drove the truck for 5.15 miles

5 0
2 years ago
Will mark brainliest if ur correct! Pls and ty
galina1969 [7]

Answer:

138

Step-by-step explanation:

Hexagon total angle = 720

170+ 277 + 135 = 582

720 - 582 = 138

7 0
3 years ago
I need urgent help with this
iren2701 [21]

Answer:

A. =4x3+9x2−25x+12

Step-by-step explanation:

(x+4)(4x−3)(x−1)

=((x+4)(4x−3))(x+−1)

=((x+4)(4x−3))(x)+((x+4)(4x−3))(−1)

=4x3+13x2−12x−4x2−13x+12

=4x3+9x2−25x+12

5 0
3 years ago
Please help!!!!
valentina_108 [34]
ANSWER

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t  + 6}{ t + 2}
where,
t \ne - 2



EXPLANATION

We want to simplify the rational expression

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }


We can observe that the numerator of the given rational expression is a quadratic trinomial and the denominator is a difference of two squares



We need to split the middle term in the numerator and rewrite the denominator as a difference of two squares to obtain,




\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{{t}^{2}  + 6t - 2t - 12}{ {t}^{2}  -  {2}^{2} }



We now factor to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{t (t+ 6) - 2(t  + 6)}{ (t  -  2)(t + 2)}


This implies that,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t - 2) (t  + 6)}{ (t  -  2)(t + 2)}


We now cancel out common factors to obtain,

\frac{ {t}^{2}  + 4t - 12}{ {t}^{2} - 4 }  =  \frac{(t  + 6)}{ (t + 2)}


The restriction is that, the denominator cannot be zero.

Thus

t + 2 \ne0


This implies that,

t  \ne - 2
6 0
3 years ago
Read 2 more answers
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