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IRISSAK [1]
2 years ago
5

1.4 divided by 0.07 Plz I need help and PLZ NO LINKS

Mathematics
2 answers:
d1i1m1o1n [39]2 years ago
6 0

Answer:

the answer is 20, i wish i could show u my work but i dont know how to add pictures :(   :)

miv72 [106K]2 years ago
4 0

I used a calculator my bad but use photot math take a picture of the problem and it will show you step by step on how to do it

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Graph the solution set to the inequality -s/2 + 5 &lt; 4<br><br><br><br><br> Please help!!!
IceJOKER [234]

Answer:

Draw a same side int. angle with s/2 as the perp. bisector

Step-by-step explanation:


5 0
3 years ago
Which function has a domain of x 25 and a range of y s3?
lions [1.4K]

Answer:

Step-by-step explanation:

The function  has a domain x ≥ 5.

This is because the function remains real for (x - 5) ≥ 0 as negative within the square root is imaginary.

Hence, (x - 5) ≥ 0

⇒ x ≥ 5

Now, for all x values that are greater than equal to 5 the value of  will be negative.

So,  

⇒  

⇒ y ≤ 3

Therefore, the range of the function is y ≤ 3. (Answer)

<em>Note: Thanks rani</em>

3 0
2 years ago
PLEASE HELP I HAVE 10 MORE MINUTES TO FINISH THIS!!!
evablogger [386]

Answer:

b

Step-by-step explanation:

add 5+3 then add 1/2 plus 3/4

7 0
3 years ago
6x^2 - 9x + 3<br> - (8x²+ 7x - 1)
Solnce55 [7]

Answer:

-2x² - 16x + 4

Step-by-step explanation:

Step 1: Write out expression

6x² - 9x + 3 - (8x² + 7x - 1)

Step 2: Distribute negative

6x² - 9x + 3 - 8x² - 7x + 1

Step 3: Combine like terms (x²)

-2x² - 9x + 3 - 7x + 1

Step 4: Combine like terms (x)

-2x² - 16x + 3 + 1

Step 5: Combine like terms (constants)

-2x² - 16x + 4

8 0
2 years ago
Read 2 more answers
The point (8,-4) lies on a circle. What is the length of the radius of this circle if the center is located at (5,-7)
Kamila [148]
Notice the picture, the radius is just the distance from the
center to a point on the circle, thus

\bf \textit{distance between 2 points}\\ \quad \\\\&#10;\begin{array}{lllll}&#10;&x_1&y_1&x_2&y_2\\&#10;%  (a,b)&#10;&({{5}}\quad ,&{{ -7}})\quad &#10;%  (c,d)&#10;&({{ 8}}\quad ,&{{ -4}})&#10;\end{array}\qquad &#10;%  distance value&#10;\\\\\\&#10;\begin{array}{llll}&#10;d = &\sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}\\&#10;&\qquad \uparrow \\&#10;&radius&#10;\end{array}

\bf \begin{array}{llll}&#10;d = &\sqrt{({{ 8}}-{{ 5}})^2 + ({{ -4}}-{{(-7)}})^2}\\&#10;&\qquad \uparrow \\&#10;&radius&#10;\end{array}&#10;\\\\\\&#10;d=\sqrt{(3)^2+(-4+7)^2}\implies d=\sqrt{3^2+3^2}\implies d=\sqrt{18}&#10;\\\\\\&#10;d=\sqrt{9\cdot 2}\implies d=\sqrt{3^2\cdot 2}\implies d=3\sqrt{2}



4 0
3 years ago
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