Nvm forget the one i posted look
1 answer:
You might be interested in
Answer:
The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
In the survey on 200 managers, 58% of the managers have caught salespeople cheating on an expense report.
This means that
95% confidence level
So , z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
The upper limit of this interval is:
The 95% confidence interval estimate of the population proportion of managers who have caught salespeople cheating on an expense report is (0.5116, 0.6484).
When solving this equation you get x = -3.
To solve this, simply follow the order of operations for solving.
----> start by dividing both sides by 5
-----> Now you can transform the front side of the equation to use negative exponents.
Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.
-3 = x