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3 years ago

5/7^3 = 5(7^x) Thank you for helping!!

Mathematics

1 answer:

SIZIF [17.4K]3 years ago

8 0

When solving this equation you get x = -3.

To solve this, simply follow the order of operations for solving.

$\frac{5}{7^{3}} = 5(7^{x} )$ ----> start by dividing both sides by 5

$\frac{1}{7^{3}} = (7^{x} )$ -----> Now you can transform the front side of the equation to use negative exponents.

$7^{-3} = 7^{x}$

Since both x and -3 are the powers of x, we can eliminate the 7 and just make the exponents equal.

-3 = x

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Let's replace $x$ with $(9a)$ and $y$ with $(-10b)$ in the expansion:

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Let's simplify a bit:

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