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lawyer [7]
3 years ago
15

MARKING BRAINLIEST!! For what value of x is the figure below a rectangle?

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
5 0
<h2><u><em>Answer: Yes it is a rectangle I don't know if that's all you want to know</em></u></h2>

<u><em></em></u>

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Help with this question please please please
Anna35 [415]

Answer:

1900 miles long

Step-by-step explanation:

5 0
3 years ago
HURRY ONLY HAVE 1 MIN!!!!!!!!!!!!!!!!
BaLLatris [955]

Answer:

100 m3

Step-by-step explanation:

2*5*10 = 10*10 *100

6 0
2 years ago
A circle with center on (7,0) with a radius of 9.
Greeley [361]

Answer:

The answer to your question is   (x - 7)² + y² = 81

Step-by-step explanation:

Data

Center = (7, 0)

radius = 9

Process

To find the standard equation of a circle, just substitute the values of the center and the radius.

Standar equation of a circle

                     (x - h)²  +  (y - k)² = r²

-Identify the values of h and k

                     h = 7    k = 0   and r = 9

-Substitution

                    (x - 7)² + (y - 0)² = 9²

-Simplification

                  (x - 7)² + y² = 81

7 0
3 years ago
Look at the picture and help answer question 7 please​
qwelly [4]
3pm we know this because 5^3= 125 so then we plug in numbers for the exponent in this case 6 which equals 15,625 now 9am plus 6 is 3pm
5 0
3 years ago
Find a closed-form solution to the integral equation y(x) = 3 + Z x e dt ty(t) , x &gt; 0. In other words, express y(x) as a fun
MrMuchimi

Answer:

y{x} = \sqrt{7+2Inx}

Step-by-step explanation:

y(x)= 3 + \int\limits^x_e {dx}/ \, ty(t) , x>0}

Let say; By y(x)= y(e)  

we have;  

y(e)= 3 + \int\limits^e_e {dt}/ \, ty= 3+0

Using Fundamental Theorem of Calculus and differentiating by Lebiniz Rule:

y^{1} (x) = 0 + 1/ xy

y^{1} = 1/xy  

dy/dx = 1/xy  

\int\limits {y} \, dxy = \int\limits \, dx/x

y^{2}/2 Inx + C

RECALL: y(e) = 3  

(3)^{2} / 2 = In (e) + C  

\frac{9}{2} =In(e)+C  

\frac{9}{2} - 1 = C

\frac{7}{2} = C  

y^{2} / 2 = In x +C

y^{2} / 2 = In x +7/2

MULTIPLYING BOTH SIDE BY 2 , TO ELIMINATE THE DENOMINATOR, WE HAVE;

y^{2} = {7+2Inx}  

y{x} = \sqrt{7+2Inx}

8 0
3 years ago
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