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Anuta_ua [19.1K]
3 years ago
15

Which names are other ways to name ∠1?

Mathematics
1 answer:
vesna_86 [32]3 years ago
4 0
∠1 is an angle formed by the two lines PF and YF at point F

We can also call this angle as ∠PFY because it indicates the point F in the middle where the angle is formed

We can call this angle as ∠YFP because it also indicates the point F in the middle where the angle is formed

we can also call this angle ∠F since F is the point where the angle is formed.

Correct answer: ∠PFY, ∠YFP, ∠F
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Given a graph for the transformation of f(x) in the format g(x) = f(kx), determine the k value.
AlexFokin [52]

Answer: C

1/4

Step-by-step explanation:

Given a graph for the transformation of f(x) in the format g(x) = f(kx),

This means that for every value of x, f(x) will take the value it would have had at kx, that is, the graph of f(x) is stretched by a factor of 1/k in the direction of positive x-direction.

Therefore, the value of k will be 1/4.

3 0
3 years ago
2,568 + (-1,452) pls help me asap !!! we are doing adding rational numbers
Kitty [74]

Answer:

1,116

Step-by-step explanation:

2568 + ( - 1452)

= 2568 - 1452 ( because + × - makes -)

= 2568 - 1452

=<u> 1,116</u>

4 0
3 years ago
Read 2 more answers
Change 1.4 to a fraction. <br> 1/4<br> 1 1/4<br> 1 1/2<br> 1 2/5
dusya [7]
1.4
= 1+ 0.4
= 1+ 4/10
= 1+ (4/2) / (10/2)
= 1+ 2/5
= 1 2/5

The final answer is 1 2/5.


3 0
3 years ago
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The demand function for a product is p=30−3q where p is the price in dollars when q units are demanded. Find the level of produc
Marina86 [1]

Answer: a) Q= 5units

b) R= $75

Step-by-step explanation:

The maximum revenue is at dR/dq = 0

Revenue = price x quantity of demand = p × q

Substituting p = 30- 3q

R = (30-3q) × q

R= 30q- 3q2 (q2 = q raised to the power of 2)

dR/dq = 30- 6q = 0

6q = 30

q= 30/6= 5

q= 5 units

R = pq= 30q- 3q2

R= 30(5) - 3( 5×5)

R= 150- 75

R= $75

Goodluck...

7 0
3 years ago
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How do you solve m/9 divided by mn squared / 3
ivolga24 [154]
\frac{m}{9}:\frac{mn^2}{3} =\frac{m}{9} \cdot \frac{3}{mn^2} =\frac{1}{3n^2}


3 0
3 years ago
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