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Fynjy0 [20]
2 years ago
9

Help help math math math

Mathematics
1 answer:
Marianna [84]2 years ago
5 0

Answer:

3

Step-by-step explanation:

Get rid of fractions:

Multiply the whole equation, i.e. all terms both sides of the equals sign, by the denominator or the lowest common multiple of all denominators if there are multiple fractions in the equation;

In this case, only one term is a fraction and therefore has a denominator (i.e. 7), so it is this number we multiply the equation by to get:

7(y) = 7(-³/₇.x) + 7(3)

7y = -3x + 21

3x + 7y = 21

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Find the volume of a cylinder with radius 5.7cm and height 10 cm, correct to 1 decimal place​
Veseljchak [2.6K]

\textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=5.7\\ h=10 \end{cases}\implies \begin{array}{llll} V=\pi (5.7)^2(10)\implies V=324.9\pi \\\\\\ V\approx 1020.7 \end{array}

8 0
2 years ago
(20 Points)
storchak [24]

Answer:

2nd option will be the answer (y=4x²+48x+146)

Step-by-step explanation:

y=4(x+6)²+2

y=4(x²+2*x*6+6²)+2 [(a+b)²=a²+2ab+b²]

y=4(x²+12x+36)+2

y=4(x²)+4(12x)+4(36)+2

y=4x²+48x+144+2

y=4x²+48x+146

5 0
3 years ago
Two cables support a 800​-lb ​weight, as shown. Find the tension in each cable.
jeka94

Answer:

  • 892 lb (right)
  • 653 lb (left)

Step-by-step explanation:

The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...

  Rcos(45°) +Lcos(75°) = 800

  Rsin(45°) -Lsin(75°) = 0

Solving these equations by Cramer's Rule, we get ...

  R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))

     = 800sin(75°)/sin(120°) ≈ 892 . . . pounds

  L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds

The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.

_____

This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...

  (right, left) = w/sin(α+β)×(sin(β), sin(α))

5 0
3 years ago
Estimate the annual wages for a clerk who works 50 weeks a year and earns $15 and hour
Pachacha [2.7K]

Let us assume that a person works for 8 hours a day.

Let us assume that the person works for 5 days a week.

Wage earned per hour = $15

So, wage earned in 8 hours = 15*8 = $120

Now, wage earned in 1 day = 120

So, wage earned in 5 days = 120*5 =$600

As the person works for 5 days in 1 week

So, in 50 weeks, he will work = 50*5 = 250 days

So, total number of hours he must have worked = 250*8 =2000 hours

Now, per hour wage = $15

wage in 2000 hours = 15*2000 = $30000

Hence, the estimated wage a person earns in 50 weeks = $30000



7 0
3 years ago
Is D the right answer for this? Thank you! - Alyssa
vesna_86 [32]
We start by ordering the values.

5, 7, 8, 10, 13, 14, 17, 17, 21

Now we find the median(middle number).

Median(b): 13
(I added (b) for "base" since we need to take more medians)
The median now divides this data into two halves.

Now we take the medians of the two remaining halves.

Median(Half1): 7.5
Median(Half2): 17

Mark off the minimum and maximum.

Min: 5
Max: 21

Now graph!

Your median(Half1) is incorrect, since your median for the first half is 9. Since our median for the first half is 7.5, the answer would be Answer Choice C.
8 0
3 years ago
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