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2 years ago

I need help with this one Q2

Mathematics

2 answers:

ArbitrLikvidat [17]2 years ago

7 0

Add 7 on both sides so the equation is 5x=-30. Then divide by 5 on both sides 5/5 cancels out, -30/5 = -6

The answer would be -6

Hope this helps

adoni [48]2 years ago

4 0

Answer:

it's b

Step-by-step explanation:

you add 7 on both sides to cancel it out. Then isolate x by dividing by 5 on both sides.

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Can someone help with this pleasee?

enot [183]

Answer:

That is so easyyyyyyyyy

Step-by-step explanation:

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3 years ago

I need help asap pls and thank you ;)

olga55 [171]

Answer:

$\text{Length of AB is }\frac{ah}{a+h}$

Step-by-step explanation:

Given △KMN, ABCD is a square where KN=a, MP⊥KN, MP=h.

we have to find the length of AB.

Let the side of square i.e AB is x units.

As ADCB is a square ⇒ ∠CDN=90°⇒∠CDP=90°

⇒ CP||MP||AB

In ΔMNP and ΔCND

∠NCD=∠NMP (∵ corresponding angles)

∠NDC=∠NPM (∵ corresponding angles)

By AA similarity rule, ΔMNP~ΔCND

Also, ΔKAP~ΔKPM by similarity rule as above.

Hence, corresponding sides are in proportion

$\frac{ND}{NP}=\frac{CD}{MP} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{AB}{PM} \\\\\frac{ND}{NP}=\frac{x}{h} \thinspace\thinspace and\thinspace\thinspace \frac{KA}{KP}=\frac{x}{h}\\\\\frac{NP}{ND}=\frac{h}{x} \thinspace\thinspace and\thinspace\thinspace \frac{KP}{KA}=\frac{h}{x}\\\\\frac{PD}{ND}=\frac{h}{x}-1 \thinspace\thinspace and\thinspace\thinspace \frac{AP}{KA}=\frac{h}{x}-1\\$

$KA(\frac{h}{x}-1)=AP$

$ND(\frac{h}{x}-1)=PD$

Adding above two, we get

$(KA+ND)(\frac{h}{x}-1)=(AP+PD)$

⇒ $(KN-AD)=\frac{x}{(\frac{h}{x}-1)}$

⇒ $a-x=\frac{x}{(\frac{h}{x}-1)}$

⇒ $a-x=\frac{x^2}{h-x}$

⇒ $x^2=ah-ax-xh+x^2$

⇒ $x(h+a)=ah$

⇒ $x=\frac{ah}{a+h}$

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3 years ago

Consider lim t → 0+ ( −2 sin(4t) sin(4t) + 2 t cos(4t) ) . using a table of values, the limiting value is

Andrej [43]

Since this is not a rational function (with undetermined values in the denominator), but just a normal expression, we can just substitute t with the value toward which the function is approaching. Since this is a continuous function, it doesn't matter from which side it's approaching 0. In this case, let t=0, then sin(4t)=0, cos(4t)=1, then -2 sin^2(4t)+2tcos(4t)=0.

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3 years ago

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Damm [24]

Answer:

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is my answer correct?

im pretty sure it is...

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Step-by-step explanation:

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