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V125BC [204]
3 years ago
9

Help with this slope ​

Mathematics
2 answers:
gladu [14]3 years ago
8 0

Answer:

20,100 I think

Step-by-step explanation:

Kazeer [188]3 years ago
7 0

Answer:

20/10

Step-by-step explanation:

goes up 20

goes to the right 10

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Solve the inequality. Graph the solution set. 23 + 156 > 5(3b + 1)
Elan Coil [88]

Answer:

b<58/5

Step-by-step explanation:

4 0
3 years ago
A container that holds sugar is shaped like a cylinder. The radius of the container is 3 inches,
kicyunya [14]

Answer:

B

Step-by-step explanation:

A cylinder is like circles staked on top of each other so you want to find the are of the top circle which is 28.26 because pi r^2 (3^2)*3.14. now you found the area of the top circle. The height is 10.5 so that means there are 10.5 layers so you multiply 28.26 by 10.5 i know its confusing im new to brainly but hopefully this answer helped you  You will get 296.73 because i rounded pi to 3.14 but the answer is B

8 0
3 years ago
I need help bad with this equation
Grace [21]

don't quote me on this but I'm pretty sure it's H multiplication property of inequality

8 0
2 years ago
Suppose that you invest $6000 into a high yield savings account that earns 2% annual interest and is compounded monthly. If you
Dmitry_Shevchenko [17]

Answer:


Step-by-step explanation:

FV   =   P (1  +  r / n)Yn

n=12

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P =6000


7 0
3 years ago
HELPPPPPPPPPPP
liubo4ka [24]
<span>(A) Find the approximate length of the plank. Round to the nearest tenth of a foot.
Given that the distance of the ground is 3ft.
In order to get the length of the plank,
we can use the this one.

cos 49 = ground / plank
cos 49 = 3 / plank
plank = cos 49 / 3
plank = 0.10 ft

</span><span>(b) Find the height above the ground where the plank touches the wall. Round to the nearest tenth of a foot.
</span><span>
The remaining angle is equal to
angle = 180 - (90+49)
angle = 41

Finding the height.
tan 41 = height / ground
tan 41 = height / 3
height = tan 41 / 3
height = 0.05 ft.

(A) 0.10 feet
(B) 0.05 feet</span>
3 0
3 years ago
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