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natulia [17]
2 years ago
13

Can someone please help with this ?

Mathematics
1 answer:
creativ13 [48]2 years ago
4 0

Answer:     -9n+20

This is the same as 20-9n

================================================

Explanation:

The jump from 11 to 2 is "minus 9"

The jump from 2 to -7 is also "minus 9".

Assuming this pattern continues on, we have an arithmetic sequence with

  • a = 11 = first term
  • d = -9 = common difference

The nth term can be found like so

a_n = a + d(n-1)\\\\a_n = 11 + (-9)(n-1)\\\\a_n = 11 -9n + 9\\\\a_n = -9n+20\\\\

Let's check the answer by trying n = 3

a_n = -9n+20\\\\a_3 = -9*3+20\\\\a_3 = -27+20\\\\a_3 = -7\\\\

This shows the third term is -7, which matches what the original sequence shows. The answer is partially confirmed. I'll let you check the other values of n. You should get 11 when trying n = 1, and you should get 2 when trying n = 2.

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You would have to add x1 + x2 and divide by 2. do the same with y1 and y2.

(1/2,-1/2)

6 0
2 years ago
A box contains different colored paper clips. The probability of drawing two red paper clips from the box without replacement is
ivann1987 [24]

Answer: 5/14 which is choice B

================================================

How I got this answer:

Define the following events

A = event of picking a red paper clip on the first selection

B = event of picking a red paper clip on the second drawing

Replacement is not made.

Now onto the probabilities for each

P(A) = 2/5 = 0.4 is given to us as this is simply the probability of picking red on the first try

P(A and B) = probability of both events A and B happeing simultaneously = 1/7

P(B|A) = probability event B occurs, given event A has occured

P(B|A) = probability of selecting red on second selection, given first selection is red (no replacement)

P(B|A) = P(A and B)/P(A)

P(B|A) = (1/7) / (2/5)

P(B|A) = (1/7) * (5/2)

P(B|A) = (1*5)/(7*2)

P(B|A) = 5/14

So if event A happens, then the chances of event B happening is 5/14

------------------

A more concrete example:

If we had 15 paperclips, and 6 of them were red, then

P(A) = (# of red)/(# total) = 6/15 = 2/5

P(B|A) = (# of red left)/(# total left) = (6-1)/(15-1) = 5/14

P(A and B) = P(A)*P(B|A) = (2/5)*(5/14) = 10/70 = 1/7

7 0
3 years ago
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Step-by-step explanation:

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Answer:

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