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3 years ago

40:14

Mathematics

1 answer:

Rashid [163]3 years ago

7 0

Answer:

x LE 6.3.

Step-by-step explanation:

For an obtuse triangle

c^2 > a^2 + b^2 where c is the longest side. So:

20^2 > x^2 + (3x)^2

400 > 10x^2

x^2 < 40

x < 6.324

x < 6.3.

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3 years ago

A line is drawn so that it passes through the points (-3,0) and (1.4). What is the slope of the line?

vladimir2022 [97]

Answer: $m=1$

Step-by-step explanation:

For this exercise you can use the following formula for calculate the slope:

$m=\frac{y_2-y_1}{x_2-x_1}$

In this case you know that the given line passes through the points (-3,0) and (1.4). Therefore you can identify that:

$y_2=0\\y_1=4\\\\x_2=-3\\x_1=1$

Then, in order to calculate the slope of this line, you must substitute the coordinates of the points into the formula:

$m=\frac{0-4}{-3-1}$

Finally, evaluating, you get that the slope of this line is the following:

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4 years ago

20. What is the slope of the line containing the points (3,8)

Lerok [7]

The answer is y= 4 + 1/3

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3 years ago

Please help

Alekssandra [29.7K]

Answer:

25 in x 15 in

Step-by-step explanation:

Given:

Length = 3/5 the width
Area = 375 in²

Let width = $x$

Therefore, length = 3/5 $x$

First create an equation for the area of the picture based on the given information for its width and length:

$\begin{aligned} \implies \textsf{Area of original picture} & = \sf width \times length\\& = x\left(\dfrac{3}{5}x\right)\\& = \dfrac{3}{5}x^2\end{aligned}$

We are told the area of the enlarged picture is 375 in². Therefore, substitute this into the equation and solve for $x$ to find the width of the enlarged picture:

$\begin{aligned}\textsf{Area} & = 375\\ \implies \dfrac{3}{5}x^2 & = 375\\ x^2 & =375 \cdot \dfrac{5}{3}\\ x^2 & =625\\ x & = \sqrt{625}\\ x& = 25\end{aligned}$

Therefore, the width of the enlarged picture is 25 in.

Substitute the found value of $x$ into the expression for length to find the length of the enlarged picture:

$\begin{aligned}\sf Length & = \dfrac{3}{5}x\\\\\implies \sf Length & = \dfrac{3}{5}(25)\\\\& = 15\: \sf in\end{aligned}$

Therefore, the dimensions of the enlarged picture are <u>25 in x 15 in</u>. The width is 25 in and the length is 15 in, as the length is 3/5 of the width.

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2 years ago

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