y-intercept: Let x = 0 and solve for y:
(x-1)^2 + (y-2)^2 = 10 => (-1)^2 + y^2 - 4y + 4) = 10
=> 1 + y^2 - 4y + 4 = 10, or y^2 - 4y -5 = 0
The solutions of this quadratic are y = 5 and y = -1.
Thus, the y-intercepts are (0, 5) and (0, -1).
Now find the x-intercepts: Let y = 0 and solve the resulting equation for x:
(x-1)^2 = 10 - (-2)^2, or (x-1)^2 = 10 - 4 = 6.
Taking the sqrt of both sides, x - 1 = plus or minus sqrt(6), or:
x = 1 +√6 and x = 1 - √6, so that the x-intercepts
are (1+√6, 0) and (1-√6, 0).
Answer:
See below
Step-by-step explanation:
(-12)²=144 while -(12²)=-144
Answer:
Step-by-step explanation:
I use 'n' as the unknown value, but you can use any letter you want as the variable.
The product of four and a number would be represented by '4 * n'. The ideal way to write this would be '4n', even though '4 * n' is also correct in value.
The square of the number would be n². Squaring a number is multiplying a number by itself.
The phrase 'difference between...' means subtraction.
Putting it together:
"The difference between the product of 4 and a number and the square of the number" would be:
Hope this helps.
first we multiply 400,000 by 1.20 which equals 480,000 which is the sales revenue for 2008 now we multiply 480,000 by 1.30 which equals 624,000
so your sales revenue for 2009 is $640,000
please mark brainliest.
Answer:
the answer to your question of finding x is,
x = 6
