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2 years ago

Which model does the graph represent?

Mathematics

2 answers:

larisa86 [58]2 years ago

4 0

Answer:

Step-by-step explanation:

A models an exponentially increasing function.

B models an exponentially decreasing function.

C models a "bell" curve, similar to the one shown.

D models a "logistic" function, an s-shaped curve that smoothly transitions between two horizontal asymptotes.

OLga [1]2 years ago

3 0

Answer: The correct one is C

Step-by-step explanation:

The gaussian curve ( the one you can see in the graph) is described by C.

You can see that A is an exponential function that only will grow as t grows.

B will decrease asymptotically to zero as t grows, the same with D, as t grows, D only can decrease.

but for C you will have the maximum when x = b, and a exponential decrease when x decrease or when x increase which forms the bell that you see in the graph.

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What in times equals 60

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3 years ago

Agiven line has the equation 10x+27-2

bagirrra123 [75]

Answer:

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2 years ago

The exponential distribution applies to lifetimes of a certain component. Its failure rate is unknown. Find the probability that

wlad13 [49]

Answer:

a) 0.0821

b) 0.0111

c) 0.0041

Step-by-step explanation:

Exponential distribution:

The exponential probability distribution, with mean m, is described by the following equation:

$f(x) = \lambda e^{-\lambda x}$

In which $\lambda$ is the decay parameter.

The probability that x is lower or equal to a is given by:

$P(X \leq x) = \int\limits^a_0 {f(x)} \, dx$

Which has the following solution:

$P(X \leq x) = 1 - e^{-\lambda x}$

Either it lasts more 5 years or less, or it survives more than 5 years. The sum of the probabilities of these events is decimal 1. So

$P(X \leq 5) + P(X > 5) = 1$

In all 3 cases, we want P(X > 5). So

$P(X > 5) = 1 - P(X \leq 5)$

In which

$P(X \leq 5) = 1 - e^{-5\lambda}$

(a) lambda=.5

$P(X \leq 5) = 1 - e^{-5*0.5} = 0.9179$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9179 = 0.0821$

(b) lambda=0.9

$P(X \leq 5) = 1 - e^{-5*0.9} = 0.9889$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9889 = 0.0111$

(c) lambda=1.1

$P(X \leq 5) = 1 - e^{-5*1.1} = 0.9959$

$P(X > 5) = 1 - P(X \leq 5) = 1 - 0.9959 = 0.0041$

7 0

3 years ago

Population Growth Using 20th-century U.S. census data,

asambeis [7]

The population of Ohio will be 10 million in the year 1970

The population growth of Ohio is represented by the function:

$P(t)=\frac{12.79}{1+2.402e^{-}0.0309t}$

P is the population in millions

t is the number of years since 1900

To find the year that the population of Ohio will be 10 million, substitute P = 10 into the function P(t) and solve for t

$10=\frac{12.79}{1+2.402e^{-}0.0309t}\\\\10(1+2.402e^{-}0.0309t)=12.79\\\\1+2.402e^{-}0.0309t=\frac{12.79}{10} \\\\1+2.402e^{-}0.0309t=1.279\\\\2.402e^{-}0.0309t=1.279-1\\\\2.402e^{-}0.0309t = 0.279\\\\e^{-}0.0309t =\frac{0.279}{2.402} \\\\e^{-}0.0309t =0.116\\\\-0.0309t=ln0.116\\\\-0.0309t=-2.154\\\\t=\frac{-2.154}{-0.0309} \\\\t=69.7$

t = 70 years (to the nearest whole number)

70 years after 1900 will be 1970

Therefore, the population of Ohio will be 10 million in the year 1970

Learn more here: brainly.com/question/25504185

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2 years ago

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Fittoniya [83]

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3 years ago

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