Thus L.H.S = R.H.S that is 2/√3cosx + sinx = sec(Π/6-x) is proved
We have to prove that
2/√3cosx + sinx = sec(Π/6-x)
To prove this we will solve the right-hand side of the equation which is
R.H.S = sec(Π/6-x)
= 1/cos(Π/6-x)
[As secƟ = 1/cosƟ)
= 1/[cos Π/6cosx + sin Π/6sinx]
[As cos (X-Y) = cosXcosY + sinXsinY , which is a trigonometry identity where X = Π/6 and Y = x]
= 1/[√3/2cosx + 1/2sinx]
= 1/(√3cosx + sinx]/2
= 2/√3cosx + sinx
R.H.S = L.H.S
Hence 2/√3cosx + sinx = sec(Π/6-x) is proved
Learn more about trigonometry here : brainly.com/question/7331447
#SPJ9
Answer:
I would say D. There is no logical explanation for the final answer but there is for everything else.
For A: Makes sense because 3x-2 are in parenthesis outside a number so you can multiply.
For B: Makes sense because you are allowed to add/subtract like terms but in this case only subtracting would make sense, (which is what they did) since you want to get all the like terms on one side.
For C: Makes sense because you are trying to simplify the equation, and they are both like terms (they are both numbers that have no letter attached to them) and they are on the opposite side making them able to be simplified.
For D: No idea what the point is.
Answer:
14
Step-by-step explanation:
<span>B. It must be the same as when he constructed the arc centered at point A.
This problem would be a lot easier if you had actually supplied the diagram with the "arcs shown". But thankfully, with a few assumptions, the solution can be determined.
Usually when constructing a perpendicular to a line through a specified point, you first use a compass centered on the point to strike a couple of arcs on the line on both sides of the point, so that you define two points that are equal distance from the desired intersection point for the perpendicular. Then you increase the radius of the compass and using that setting, construct an arc above the line passing through the area that the perpendicular will go. And you repeat that using the same compass settings on the second arc constructed. This will define a point such that you'll create two right triangles that are reflections of each other. With that in mind, let's look closely at your problem to deduce the information that's missing.
"... places his compass on point B ..."
Since he's not placing the compass on point Q, that would imply that the two points on the line have already been constructed and that point B is one of those 2 points. So let's look at the available choices and see what makes sense.
A .It must be wider than when he constructed the arc centered at point A.
Not good. Since this implies that the arc centered on point A has been constructed, then it's a safe assumption that points A and B are the two points defined by the initial pair of arcs constructed that intersect the line and are centered around point Q. If that's the case, then the arc centered around point B must match exactly the setting used for the arc centered on point A. So this is the wrong answer.
B It must be the same as when he constructed the arc centered at point A.
Perfect! Look at the description of creating a perpendicular at the top of this answer. This is the correct answer.
C. It must be equal to BQ.
Nope. If this were the case, the newly created arc would simply pass through point Q and never intersect the arc centered on point A. So it's wrong.
D.It must be equal to AB.
Sorta. The setting here would work IF that's also the setting used for the arc centered on A. But that's not guaranteed in the description above and as such, this is wrong.</span>
Answer: 131 magazines per hour
Step-by-step explanation:
Peggy delivered 328 magazines in 2.5 hours.
To find out the rate at which she delivered these magazines, divide the number of magazines by the time taken to deliver them:
= Magazines / Time in hours
= 328 / 2.5
= 131 magazines per hour
