Answer:
6 hope you get the point.
X=3 because you have to isolate the variable by dividing each side by factors that don’t contain the variable .
Answer: See explanation
Step-by-step explanation:
Your question isn't complete but I'm assuming that you want to calculate the radius.
Circumference of a circle = 2πr
where Circumference = 18.9 meters
Radius = Unknown
π = 3.14
We then put the values into the formula which will be:
C = 2πr
18.9 = 2 × 3.14 × r
18.9 = 6.28r
r = 18.9 / 6.28
r = 3
The radius = 3 meters
Assuming you probably want to get the diameter, we multiply the radius by 2. This will be:
= 2 × 3
= 6 meters
Answer:
Step-by-step explanation:
Note that
![x^{3/4 } = \sqrt[4]{x^3}](https://tex.z-dn.net/?f=x%5E%7B3%2F4%20%7D%20%3D%20%5Csqrt%5B4%5D%7Bx%5E3%7D)
![y^{3/8 } = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=y%5E%7B3%2F8%20%7D%20%3D%20%5Csqrt%5B8%5D%7By%5E3%7D)
So,
![\sqrt[4]{x^3} = \sqrt[8]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E3%7D%20%3D%20%20%5Csqrt%5B8%5D%7By%5E3%7D)
![( \sqrt[4]{x^3} ) ^8= ( \sqrt[8]{y^3} )^8](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20%28%20%5Csqrt%5B8%5D%7By%5E3%7D%20%29%5E8)
![( \sqrt[4]{x^3} ) ^8= y^3](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%20%5E8%3D%20%20y%5E3)
Once
![( \sqrt[4]{x^3} )^8 = (( \sqrt[4]{x^3} )^4)^2= (x^3)^2 = x^6](https://tex.z-dn.net/?f=%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E8%20%3D%20%28%28%20%5Csqrt%5B4%5D%7Bx%5E3%7D%20%29%5E4%29%5E2%3D%20%28x%5E3%29%5E2%20%3D%20x%5E6)
![x = \sqrt[6]{y^3}](https://tex.z-dn.net/?f=x%20%3D%20%20%5Csqrt%5B6%5D%7By%5E3%7D)
Answer:
x=1.816298 or x=−1.162524
Step-by-step explanation:
Step 1: Multiply both sides by x^2.
x2=x4−3x3+8x2−16
x2−(x4−3x3+8x2−16)=x4−3x3+8x2−16−(x4−3x3+8x2−16)(Subtract x^4-3x^3+8x^2-16 from both sides)
−x4+3x3−7x2+16=0
(Use quartic formula)
x=−1.162524,1.816298
Check answers. (Plug them in to make sure they work.)
x=1.816298(Works in original equation)
x=−1.162524(Works in original equation)
