Answer:
me does she speak engilsh
Explanation:
Explanation:
B. They combine and compress large files into a zip file for sending through email
Answer:
C++ code explained below
Explanation:
#include<bits/stdc++.h>
#include <iostream>
using namespace std;
int FiboNR(int n)
{
int max=n+1;
int F[max];
F[0]=0;F[1]=1;
for(int i=2;i<=n;i++)
{
F[i]=F[i-1]+F[i-2];
}
return (F[n]);
}
int FiboR(int n)
{
if(n==0||n==1)
return n;
else
return (FiboR(n-1)+FiboR(n-2));
}
int main()
{
long long int i,f;
double t1,t2;
int n[]={1,5,10,15,20,25,30,35,40,45,50,55,60,65,70,75};
cout<<"Fibonacci time analysis ( recursive vs. non-recursive "<<endl;
cout<<"Integer FiboR(seconds) FiboNR(seconds) Fibo-value"<<endl;
for(i=0;i<16;i++)
{
clock_t begin = clock();
f=FiboR(n[i]);
clock_t end = clock();
t1=double(end-begin); // elapsed time in milli secons
begin = clock();
f=FiboNR(n[i]);
end = clock();
t2=double(end-begin);
cout<<n[i]<<" "<<t1*1.0/CLOCKS_PER_SEC <<" "<<t2*1.0/CLOCKS_PER_SEC <<" "<<f<<endl; //elapsed time in seconds
}
return 0;
}
Answer:
A ) 200 Zombie systems
B ) 200 Zombie systems
Explanation:
maximum uplink data rate : 512 kbps = 512 * 1000 * 8 = 4096000 bits/sec
Determine the number of 512 byte ICMP echo packets = 512 * 8 = 4096 bits
hence the maximum number of 512-byte ICMP echo request (ping) packets a single zombie computer can send per second = 400 packets/sec
i.e. for 512kbps = 400 packets/sec
Determine the number of Zombie systems that the attacker will need to flood a target server
A) For a fast ethernet
A fast ethernet = 100 mbps
The number of Zombie systems needed = 1 zombie system * 200
and 1 zombie system = 512 kbps
therefore for a Fast ethernet the number of zombies systems needed = 200
B) For A Gigabit Ethernet
same as a fast ethernet system i.e. = 200
Answer:
exam result mostly in colleges and high schools
