Please help me I really need this
2 answers:
Answer:
8C5 = 56
Step-by-step explanation:
The formula for nCk is ...
nCk = n!/(k!(n-k)!)
Then the value of 8C5 is ...
8!/(5!(8-5)!) = 8·7·6/(3·2·1) = 8·7
8C5 = 56
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<em>Additional comment</em>
The larger of the denominator factorials will cancel most of the factors of the numerator. The remaining denominator factors can be factored from the remaining numerator values to simplify the problem of doing the math by hand. Most graphing calculators and all spreadsheets can compute this function for you.
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<span>f = v + at
Subtract v from both sides.
f - v = at
Divide both sides by a.
(f - v)/a = t
Switch sides.
t = (f - v)/a
</span>
Subtract v from both sides.
f - v = at
Divide both sides by a.
(f - v)/a = t
Switch sides.
t = (f - v)/a
We can start from the given line's coefficients and translate the line from the origin to the given point.
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk
4(x -(-2)) -(y -3) = 0
4x +8 -y +3 = 0
The equation of the desired line is ...
4x -y = -11
_____
For standard form line ax+by=c, any parallel line will have only a different value of c. For c=0, the line goes through the origin (0, 0). To make it go through point (h, k) we can write it as
a(x-h) +b(y-k) = 0
which is completely equivalent to
ax +by = ah +bk