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7nadin3 [17]
2 years ago
5

Which of the following is equivalent to x^5y^2/xy^2 when x is not equal to 0 and y is not equal to 0

Mathematics
1 answer:
vichka [17]2 years ago
6 0

x^5y^2/xy^2

= x^5-1 * y^2-2

= x^4

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3/8+3/10 in lowest form
emmasim [6.3K]
Find the common denominator.

8 and 10 have the common denominator of 80.

So 30/80 + 24/80

= 54/80

But we have to simplify it.
54/80 = 27/40
3 0
3 years ago
Find the slope of the line that passes through points (3,5) and (8,5)
Katyanochek1 [597]

Answer: m = 0

Step-by-step explanation: To solve this problem, we don't even have to use our slope formula. It's important to understand that when we have the same <em>y</em> coordinate in our first ordered pair and our second ordered pair, this means that the line will be flat or horizontal.

When a line is horizontal, it means the line has a slope of zero.

We use the variable <em>m</em> to represent slope.

So here, we can say that <em>m = 0</em>.

4 0
3 years ago
4 5/2 in simplest form
egoroff_w [7]
4 5/2 is 6 1/2 in simplest form!
5 0
3 years ago
Read 2 more answers
Please answer below :-)
katrin2010 [14]

Step-by-step explanation:

\frac{2x - 1}{4}  +  \frac{x}{3}  = 2

find a common denominator of 12 for each fraction

\frac{3}{3}  \times  \frac{(2x - 1)}{4}  +  \frac{4}{4}  \times  \frac{x}{3}  =  \frac{12}{12}  \times  \frac{2}{1}

\frac{6x - 3}{12}  +  \frac{4x}{12}  =  \frac{24}{12}

\frac{6x - 3 + 4x}{12}  =  \frac{24}{12}

\frac{10x - 3}{12}  =  \frac{24}{12}

multiply both sides by 12

12 \times  \frac{10x - 3}{12}  =  \frac{24}{12}  \times 12

12s cancel out

10x - 3 = 24

add three to both sides

10x - 3 + 3 = 24 + 3

10x = 27

divide both sides by 10

\frac{10x}{10}  =  \frac{27}{10}

The tens on the left side cancel

x =  \frac{27}{10}  = 2.7

4 0
2 years ago
The equation y = x + 1 defines the relationship between x and y, where x is the input and y is the output. Which statements abou
vichka [17]
Hey there!

Let's go through all of our options.

A) It's defintely not curved; it's written in slope intercept form and is indeed a straight line.

B) Yes, the graph is a straight line. Although it's at an angle, it has no curves or flaws, and is completely straight.

C) The graph is not vertical. It has a y intercept and slope and therefore isn't. That's because it has a rate of change, and it crosses the y axis at some point depending on the slope, or rise over run. Vertical lines really don't have that.

D) Yes, the graph is a function. This is because it does not have two x values for one y, and does not fail the straight line test, which states that you can place a straight line anywhere on the graph and it can only go through one point.

E) This is false. If we put in -5 as our input, we add 1 and get -4, which is a negative output. Your output here depends on the input you put in, and the sign usually remains considering it's +1.

F) This graph does not pass through the origin. This is because the origin has a point at 0,0 and since it's x+1, it would be 0,1 instead because your output is adding one to that 0.

Hope this helps!

8 0
3 years ago
Read 2 more answers
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