The square of a number is added to 6

If y varies directly as x, and y =15 as x= -3, find y for the x-value of 6.

VMariaS [17]

Answer:

the answer is -30.

Step-by-step explanation:

for each x-value, you will multiply it by -5 to get your y-value. i say this because if y-15 when x=-3, if you divide the x from y (so 15/-3) you get -5 which is the number in which y varies by. so you will take 6 and multiply it by -5 which gives you -30.

8 0

3 years ago

What is the diameter of circle 0?

Marina86 [1]

Answer:

8

Step-by-step explanation:

diameter is the radius times 2

3 0

2 years ago

Over the summer Mr.Patel refilled a bird feeder 24 time using 6 cups of seeds each time.A bag of seeds holds 32 cups. How many b

nalin [4]

Answer:

The equation representing the problem is $x=\frac{24\times 6}{32}$ .

Mr. Patel used 5 bags of seeds.

Step-by-step explanation:

Given:

Number of times bird feeder refilled =24

Number of cups of seeds used each time = 6 cups

Number of seeds each bag holds = 32 cups.

We need to write the equation to represent the problem.

Solution.

Let the total number of bag of seed be 'x'.

First we will find the Total number of cups of seeds used.

Now we can say that;

Total number of cups of seeds used can be calculated by multiplying Number of times bird feeder refilled by Number of cups of seeds used each time.

framing in equation form we get;

Total number of cups of seeds used = $24\times6 \ cups$

Now We know that;

1 bag holds = 32 cups

Total number of bags required = $24\times6 \ cups$

So we can say that;

Total number of bags required is equal to Total number of cups of seeds used divided by number of seed hold by each bag.

framing in equation form we get;

$x=\frac{24\times 6}{32}$

Hence the equation representing the problem is $x=\frac{24\times 6}{32}$ .

On solving we get;

$x=4.5$

Since bags cannot be bought in half or in decimal value.

Hence we can say Mr. Patel used 5 bags of seeds.

7 0

3 years ago

If the difference when −15 is subtracted from a number is twice the difference when 24 is subtracted from the same number, what

kirill [66]

Answer:

The number is 39

Step-by-step explanation:

Let the unknown number be <em>x</em>:

$(x-(-15))=2(x-24)\\x+15=2x-24\\39=x\\\therefore x=39$

4 0

3 years ago

In a football or soccer game, you have 22 players, from both teams, in the field. what is the probability of having at least any

Tamiku [17]

We can solve this problem using complementary events. Two events are said to be complementary if one negates the other, i.e. E and F are complementary if

$E \cap F = \emptyset,\quad E \cup F = \Omega$

where $\Omega$ is the whole sample space.

This implies that

$P(E) + P(F) = P(\Omega)=1 \implies P(E) = 1-P(F)$

So, let's compute the probability that all 22 footballer were born on different days.

The first footballer can be born on any day, since we have no restrictions so far. Since we're using numbers from 1 to 365 to represent days, let's say that the first footballer was born on the day $d_1$ .

The second footballer can be born on any other day, so he has 364 possible birthdays:

$d_2 \in \{1,2,3,\ldots 365\} \setminus \{d_1\}$

the probability for the first two footballers to be born on two different days is thus

$1 \cdot \dfrac{364}{365} = \dfrac{364}{365}$

Similarly, the third footballer can be born on any day, except $d_1$ and $d_2$ :

$d_3 \in \{1,2,3,\ldots 365\} \setminus \{d_1,d_2\}$

so, the probability for the first three footballers to be born on three different days is

$1 \cdot \dfrac{364}{365} \cdot \dfrac{363}{365}$

And so on. With each new footballer we include, we have less and less options out of the 365 days, since more and more days will be already occupied by another footballer, and we can't have two players born on the same day.

The probability of all 22 footballers being born on 22 different days is thus

$\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

So, the probability that at least two footballers are born on the same day is

$1-\dfrac{364\cdot 363 \cdot \ldots \cdot (365-21)}{365^{21}}$

since the two events are complementary.

8 0

3 years ago