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Y_Kistochka [10]
3 years ago
8

If y varies directly as x, and y =15 as x= -3, find y for the x-value of 6.

Mathematics
1 answer:
VMariaS [17]3 years ago
8 0

Answer:

the answer is -30.

Step-by-step explanation:

for each x-value, you will multiply it by -5 to get your y-value. i say this because if y-15 when x=-3, if you divide the x from y (so 15/-3) you get -5 which is the number in which y varies by. so you will take 6 and multiply it by -5 which gives you -30.

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In the equation y=mx+b, what does the x stand for? And, in the equation y=3x+6 how would I solve for y?
ladessa [460]

Answer:

x stays x in both equations so x stands for x

Step-by-step explanation:

y=3x+6

you can put this into a graphing caculator or draw it yourself.

6 is the y value when x equals 0. and the 3 represents the slope so then it is solved for any y value

7 0
3 years ago
Find the surface are of the composite figure.
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Answer:

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7 0
3 years ago
Consider the polynomial p(x) = x^3 + 4x^2 + 6x − 36.
Nady [450]

Answer:

a. attached graph; zero real: 2

b. p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

Step-by-step explanation:

p(x) = x³ + 4x² + 6x - 36

a. Through the graph, we can see that 2 is a real zero of the polynomial p. We can also use the Rational Roots Test.

p(2) = 2³ + 4.2² + 6.2 - 36 = 8 + 16 + 12 - 36 = 0

b. Now, we can use Briott-Ruffini to find the other roots and write p as a product of linear factors.

2 |  1     4     6    -36

     1      6    18     0

x² + 6x + 18 = 0

Δ = 6² - 4.1.18 = 36 - 72 = -36 = 36i²

√Δ = 6i

x = -6±6i/2 = 2(-3±3i)/2

x' = -3-3i

x" = -3+3i

p(x) = (x - 2)(x + 3 + 3i)(x + 3 - 3i)

c. the solutions are 2, -3-3i and -3+3i

4 0
3 years ago
Determine the area of the circular floor space inside the igloo, given the walls were 0.3m thick
Vanyuwa [196]
More details are required.
8 0
3 years ago
The linear combination method gives a solution of (–4, 2) for which of these systems of linear equations?
otez555 [7]

The solution (-4,2) satisfies for the system of linear equations 3x + 13y = 14; 6x + 11y = -2

<u>Step-by-step explanation:</u>

Step 1:

Given detail is the solution of the equations (-4, 2) ie, x= - 4 and y = 2

This implies that this solution should satisfy the given linear equations.

Step 2:

Substitute values of x and y in the equations and verify whether the right hand side equals the left hand side.

System 1 Eq(1) ⇒ LHS = 3(-4) + 13 (2) = -12 + 26 = 14 = RHS

System 1 Eq(2) ⇒ LHS = 6(-4) + 11(2) = -24 + 22 = -2 = RHS

Therefore, the first system of linear equations satisfy the condition.

4 0
3 years ago
Read 2 more answers
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