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ludmilkaskok [199]
3 years ago
14

Which were british field marshal bernard montgomery contributions.

SAT
1 answer:
Scrat [10]3 years ago
7 0

C. He defeated the Axis armies of Italy and Germany at El Alamein, Egypt.


D. He defeated the German army at the Battle of the Bulge.

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My friend flunked 8th grade but yet continued onto high school. But note, your parents can say yes to holding you back if a teacher recommends so. But other than that, you probably won’t get held back. But you will get held back in high school if you don’t pass.
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Anyone that has taken the SAT with a decent score, can you give me some tips please for saturday?
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4 0
3 years ago
how many watts are consumed in a circuit having a power factor of 0.2 if the input is 100 vac at 4 amperes?
Andrei [34K]

The watts that are consumed in a circuit that is having power factor of 0.2 and input is 100V at 4 ampheres is 80 watts.

Given that power factor is 0.2, input is 100V and electricity current be 4 amperes.

We are required to find the number of watts that are consumed in circuit.

An electric current is basically a stream of charged particles, such as electrons or ions, moving through an electrical conductor or space.

Power factor is basically the ratio of working power, measured in kilowatts , to apparent power, measured in kilovolt amperes.

Number of watts that are consumed will be=100*0.2*4

=80 watts

Hence the watts that are consumed in a circuit that is having power factor of 0.2 and input is 100V at 4 ampheres is 80 watts.

Learn more about electric current at brainly.com/question/1100341

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5 0
2 years ago
What maximum amount of ammonia in kilograms can be synthesized from 5.22 kg of h2 and 31.5 kg of n2?
Fiesta28 [93]

Consider the unbalanced reaction,

H₂ + N₂   ===>   NH₃

Balance it to get

3 H₂ + N₂   ===>   2 NH₃

This tells you that for every 3 moles of H₂ and 1 mole of N₂ among the reactants, 2 moles of NH₃ are produced.

Look up the molar masses of each component element:

• H : 1.008 g/mol     ===>   H₂ : 2.016 g/mol

• N : 14.007 g/mol     ===>   N₂ : 28.014 g/mol

• NH₃ : 17.031 g/mol

Convert the given mass to moles for each reactant:

• H₂ :

(5.22 kg) × (1000 g/kg) × (1/2.016 mol/g) ≈ 2589.29 mol

• N₂ :

(31.5 kg) × (1000 g/kg) × (1/28.014 mol/g) ≈ 1124.44 mol

Now,

(2589.29 mol H₂) : (1124.44 mol N₂) ≈ (2.30 mol H₂) : (1 mol N₂)

so that the amount of N₂ consumed is

(2589.29 mol H₂) × (1 mol N₂) / (3 mol H₂) ≈ 863.095 mol N₂

leaving an excess of about 261.343 mol N₂, and producing

(2589.29 mol H₂) × (2 mol NH₃) / (3 mol H₂) ≈ 1726.19 mol NH₃

Convert this to a mass :

(1726.19 mol) × (17.031 g/mol) × (1/1000 kg/g) ≈ 29.3987 kg

So, up to 29.4 kg of NH₃ can be synthesized.

4 0
3 years ago
Read the sentence:
nikdorinn [45]

Answer:

B

Explanation:

i think that's competence meaning

7 0
3 years ago
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