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jekas [21]
3 years ago
12

What is the image point of (3,-5) after a translation right 3 units and 1 up unit

Mathematics
1 answer:
Hunter-Best [27]3 years ago
7 0
(6,-4) is the correct answer
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Use properties to evaluate 2/3 • (- 3/4 / 1/8) 1/3<br><br> A.-4<br> B. 4<br> C.-4/3<br> D.4/3
Bond [772]

Answer:

Step-by-step explanation:

First you do the division in parentheses and you get (-3/4*8/1) = -24/4 = -6

The new exercise becomes 2/3 *(-6)*1/3

Next, since there are only multiplication we have to do then in order from left to right so we have

-12/3*1/3 = -12/9

We can simplify by 3 and we get -4/3

Anwer choice C

7 0
3 years ago
Mr. Niles has a box of accessories for clarinets he has a total of 42 objects.
icang [17]

Answer:

12 mouthpieces, 24 reeds, 6 neck straps

Step-by-step explanation:

42 objects - 12 mouthpieces

= 30 objects left consisting of reeds and neckstraps

4 times as many reeds as neckstraps

think of it as 5 groups, 4 are reeds and 1 of nexkstraps

so divide 30 by 5 to get 6 per part.

4 of those parts = 24

1 of the parts = 6

so reeds = 24

neckstraps is 6

mouthpieces = 12

7 0
3 years ago
Which one of the following does not describe Aaron Burr?
lord [1]

Answer:

Aaron Burr wasn't a brilliant politician.

Step-by-step explanation:

Aaron Burr was an American politician and the third Vice President of the United States from 1801 to 1805. In 1800, he ran for the Democratic-Republicans with Thomas Jefferson. Jefferson was supposed to be president and Burr vice president, but the then presidential election rules gave Jefferson and Burr equal votes in the Electoral College, and the election was ultimately decided in the House of Representatives. There, it were Jefferson and Burr's political rivals, the Federalists, who made the difference. Alexander Hamilton, the leader of the Federalists, eventually urged his party to back Jefferson, which helped make Hamilton and Burr deadly rivals. Burr had to settle for vice president under Jefferson.

On July 11, 1804, Burr challenged Hamilton to a duel in which Burr would fire the deadly shot. Burr was charged with murder in two states, but never prosecuted. After a short flight south, Burr returned to Washington to serve his term as vice president.  

After his term, Burr was suspected of involvement in a plot to create a separate republic in the then Southwestern US, headed by himself. For this he was arrested in 1807. He was tried for treason but was acquitted. After a stay abroad, Burr returned to New York in 1812 and resumed his career as a lawyer. He died in 1836 at the age of eighty and was buried in Princeton, New Jersey.

6 0
3 years ago
Five angles of a hexagon measure 119, 129, 104, 139, and 95. What is the measure of the sixth angle?
SIZIF [17.4K]

Answer:

134°

Step-by-step explanation:

The sum of interior angles of a regular polygon is: (n - 2)180

Hexagon has six sides, n is 6

Sum of it's angles is (6 - 2)180 = 720

sum of our hexagon:

119 + 129 + 104 + 139 + 95 + x = 720°

x is 134°

8 0
4 years ago
425 students in the 9th, 10th, and 11th grades were asked if they ride the bus to school. The results are shown in the two-way f
Ipatiy [6.2K]

The true statements are:

  • 44/85 of the student surveyed do not ride the bus to school
  • About 32% of the students are in the 9th grade

The false statements are:

  • 64% of the students are 11th graders
  • 134/150 of the students surveyed are in 9th or 10th grade

<h3>How to interpret the two-way frequency table</h3>

<u>The students that do not ride bus to school</u>

From the table, 220 students do not ride bus to school.

So, the proportion of students that do not ride bus to school is:

p=\frac{220}{425}

Simplify

p=\frac{44}{85}

Hence, this statement is true

<u>The 9th graders </u>

From the table, 134 students are 9th graders

So, the proportion of students that are 9th graders is:

p=\frac{134}{425}

Divide

p=0.315

Approximate, and represent as percentage

p=32\%

Hence, this statement is true

<u>The 11th graders </u>

From the table, 141 students are 11th graders

So, the proportion of students that are 11th graders is:

p=\frac{141}{425}

Divide

p=0.331

Approximate, and represent as percentage

p=33\%

Hence, this statement is false

<u>The 9th or 10th graders </u>

From the table, 134 + 150 students are 9th or 10th graders

So, the proportion of students that are 11th graders is:

p=\frac{134 + 150}{425}

p=\frac{284}{425}

Hence, this statement is false

Read more about two-way frequency table at:

brainly.com/question/16148316

4 0
3 years ago
Read 2 more answers
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