To find the area of the arena, you will need to find the areas of the rectangular spaces and the 2 semicircles. Because the formulas are given, I will just substitute in the values and show the work for finding the areas.
To find the perimeter, you will look at the distances of lines that take you around the space. Because two of these spaces are half circles, you will need to find the circumference of the full circle.
Also, the answers need to be given in meters, so all units given in centimeters will be divided by 100 to convert them to meters.
Perimeter:
C= 3.14 x 20 m
C = 62.8 meters
62.8 + 8 + 25 + 8 + 5 + 8 + 10 + 8 + 40= 174.8 meters for the Perimeter
Area:
A = 25 x 8
A = 200 square meters
A = 10 x 8
A = 80 square meters
A = 20 x 40
A = 800 square meters
A = 3.14 x 10^2
A = 314 square meters
Total Area: 314 + 800 + 80 + 200= 1394 square meters
Differentiate each term with respect to x , then solve y'.
dy/dx = y+2x^3/ x(1+x)
Answer:
Its option number 2 perhaps, sorry if im wrong
Step-by-step explanation:
Yeah not just one letter but two letters perpendicular to another two letters. Each 2 letters like AB is a straight line which is crossed by another 2 letters making it perpendicular.
