Answer:
71
Step-by-step explanation:
The question says we have 140 bags and we have 4 models
bags have buttons but no zips.
bags have zips but no buttons.
bags have neither zips nor buttons
bags have both zips and buttons
We don't know how many bags have zips and buttons but we know how many bags are produced. And other 3 types of bags number. So we can calculate
140-47-48-22=23
That means we have 23 bags that have zips and buttons
and
48 of the bags have zips too. that means we have 48+23=71 bags that have zips on them.
Answer:
![-8x+6](https://tex.z-dn.net/?f=-8x%2B6)
Step-by-step explanation:
we know that
The expression Subtract
from
is equivalent to the algebraic equation
![=(-3x+4)-(5x-2)](https://tex.z-dn.net/?f=%3D%28-3x%2B4%29-%285x-2%29)
![=-3x+4-5x+2](https://tex.z-dn.net/?f=%3D-3x%2B4-5x%2B2)
Group terms that contain the same variable
Combine like terms
![=(-3x-5x)+(4+2)](https://tex.z-dn.net/?f=%3D%28-3x-5x%29%2B%284%2B2%29)
![=(-8x)+(6)](https://tex.z-dn.net/?f=%3D%28-8x%29%2B%286%29)
![=-8x+6](https://tex.z-dn.net/?f=%3D-8x%2B6)
<u>Answer</u>-
<em>The total capacitive reactance of the circuit is </em>442.10<em> Ω.</em>
<u>Solution-</u>
Three capacitors, a 12 mF, a 20 mF, and a 30 mF, are connected in series to a 60 Hz source.
The effective/equivalent capacitance of the circuit is,
![\Rightarrow \dfrac{1}{C}=\dfrac{1}{12}+\dfrac{1}{20}+\dfrac{1}{30}\\\\\Rightarrow \dfrac{1}{C}=\dfrac{5+3+2}{60}=\dfrac{10}{60}=\dfrac{1}{6}\\\\\Rightarrow C =6\ mF](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1%7D%7BC%7D%3D%5Cdfrac%7B1%7D%7B12%7D%2B%5Cdfrac%7B1%7D%7B20%7D%2B%5Cdfrac%7B1%7D%7B30%7D%5C%5C%5C%5C%5CRightarrow%20%5Cdfrac%7B1%7D%7BC%7D%3D%5Cdfrac%7B5%2B3%2B2%7D%7B60%7D%3D%5Cdfrac%7B10%7D%7B60%7D%3D%5Cdfrac%7B1%7D%7B6%7D%5C%5C%5C%5C%5CRightarrow%20C%20%3D6%5C%20mF)
When capacitors are joined in series, the total value of capacitance in the circuit is equal to the reciprocal of the sum of the reciprocals of capacitance of all the individual capacitors.
We know that,
![X_c=\dfrac{1}{2\pi fC}](https://tex.z-dn.net/?f=X_c%3D%5Cdfrac%7B1%7D%7B2%5Cpi%20fC%7D)
Where,
= Capacitive Reactance (in Ω)
f = frequency (in Hz)
C = Capacitance (in F)
Here given,
= ??
f = 60 Hz
C = 6 mF =
F
Putting the values in the formula,
![X_c=\dfrac{1}{2\pi \times 60\times 6\times 10^{-6}}](https://tex.z-dn.net/?f=X_c%3D%5Cdfrac%7B1%7D%7B2%5Cpi%20%5Ctimes%2060%5Ctimes%206%5Ctimes%2010%5E%7B-6%7D%7D)
![X_c=\dfrac{10^{6}}{720\pi}](https://tex.z-dn.net/?f=X_c%3D%5Cdfrac%7B10%5E%7B6%7D%7D%7B720%5Cpi%7D)
![X_c=442.10\ \Omega](https://tex.z-dn.net/?f=X_c%3D442.10%5C%20%5COmega)
Therefore, the total capacitive reactance of the circuit is 442.10 Ω.
Answer:
chocolate chip and oatmeal raisin
Step-by-step explanation:
those two combined are a total of 5 cups