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iren [92.7K]
3 years ago
7

(05.01 MC)

Computers and Technology
1 answer:
KiRa [710]3 years ago
4 0

Answer:

0xff

Explanation:

the thing is that hexadecimal always starts with 0x

and theres only one option that starts with 0x

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yes

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Explanation:

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Create a loop that will output all the numbers less than 200 that are evenly divisible (meaning remainder is zero) by both 5 and
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Answer:

public class num7 {

   public static void main(String[] args) {

       int n =1;

       while(n<200){

           if(n%5==0 && n%7==0){

               System.out.print(n);

               System.out.print(",");

           }

           n++;

       }

   }

}

Explanation:

  • In Java programming Language
  • Create and initialize an int variable (n=1)
  • Create a while loop with the condition while (n<200)
  • Within the while loop use the modulo operator % to check for divisibility by 5 and 7
  • Print the numbers divisible by 5 and 7
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Answer:

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