This program uses a conditional to determine if seafood is safe to consume.
IF (seafood = "mollusk" OR daysFrozen ≥ 7) { rating ← "safe" } ELSE { rating ← "unsafe" }
In which situations will rating be "safe"?
️Note that there may be multiple answers to this question.
Choose all answers that apply:Choose all answers that apply:
1. When sea food is mollusk and day frozen is 1
2.When sea food is mollusk and day froze is 9
3. When see food salmon and day frozen is 7
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Answer:
C, Both of these.
Explanation:
You can take notes either way. It's just your preference. Hope this helps :)
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
Carlos Should use a Security Camera to keep track of his physical hardware. Carlos can then use a computer to monitor the security cameras.
