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2 years ago

Please help me !!!!!!

Mathematics

1 answer:

DIA [1.3K]2 years ago

7 0

Answer:

(x, y) = (2, 2)

Step-by-step explanation:

The graph is attached.

Both equations are in slope-intercept form:

y = mx +b . . . . . . line with slope m and y-intercept b

The graph of the first equation intersects the y-axis at +3, and has a slope (rise/run) of -1/2. That is, it decreases 1 unit for each 2 units to the right.

The graph of the second equation intersects the y-axis at -4, and has a slope of +3. It will increase 3 units for each unit to the right.

The point of intersection of the graphed lines is (2, 2).

The solution is (x, y) = (2, 2).

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Bill pays $49 for an item after it has been discounted 30%. What was the original price of the item?

makvit [3.9K]

If an item has been discounted 30%, then it is currently worth 70% of the original price. This tells us that $49 is 70% of the original price. Therefore, you need to divide $49 by 70% to get your answer (you have to work backwards; remember that you would have multiplied the original number by 0.7 to get 49):
49÷(70/100)= $70
Therefore, the price of the original product was $70

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3 years ago

PLZ HELP ME! THIS IS MIDDLE SCHOOL LEVEL MATH!!!!

melomori [17]

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3 years ago

Which of the following represents the transformation of abc

dusya [7]

Answer:

option (3) and (4)

Step-by-step explanation:

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2 years ago

A bat and a ball cost one dollar and ten cents in total. The bat costs a dollar more than the ball. How much does the ball cost?

motikmotik

X = bat
y = ball

x + y = 1.10

x = y + 1.00

Plug y + 1 in for x

(y+1) + y = 1.1

2y + 1 = 1.1

2y = 0.1

y = 0.05

If the ball is 5 cents, then the bat is 1.1-0.05= $1.05

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3 years ago

The class of 2004 holds a reunion each year. In 2005, 87.5% of the 120 graduates attended. In 2006, 90 students went, and in 200

vampirchik [111]

Answer:

15 students

Step-by-step explanation:

% of students attended reunion in 2005 = 87.5% of 120

no of students attended reunion in 2005 = 87.5/100 * 120 = 105.

no of students attended reunion in 2006 = 90

no of students attended reunion in 2007 = 75

So , the series for the given year is

105, 90, 75

we can see that this arithmetical progression series

in arithmetical progression series

common difference is = nth term - (n-1)th term

lets takes 3rd and second term as nth term and (n-1)th term

common difference(d) is =75 - 90 = -15

n th term for any arithmetical progression series is given by

nth term = a + (n-1) d

where a is the first term

n is the nth term

d is the common difference

we have to calculate number of students in reunion of of 2010

as reunion began from 2005

2005,2006,2007,2008,2009,2010

so, 2010 is 6th term in series of 105, 90, 75....

6th term = a + (n-1) d

a is 90

6th term = 90+ (6-1)* -15

6th term = 90+ (5)* -15 = 90 - 75 = 15.

Thus, 15 students will attend reunion of 2010

5 0

3 years ago