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3 years ago

The area of a rectangular pool table is: x2 + 14x +40. What are the dimensions of the table?

Mathematics

1 answer:

fiasKO [112]3 years ago

3 0

Answer:

the width is (x + 4) and the length is (x + 10)

Step-by-step explanation:

The area of a rectangle is given by A = L * W, where L is the length and W the width.

If we factor the given x^2 + 14x + 40, we get (x + 10)(x + 4). Thus, the width is (x + 4) and the length is (x + 10).

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On a piece of paper, graph f(x) 2x>3

adell [148]

Answer: jibjabjobjab it’s there

Step-by-step explanation:

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3 years ago

A = a+b+c / 3

IgorLugansk [536]

The equation given in the question is

<span>A = a+b+c / 3
3A = a + b + c
3A - a - c = b

From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.</span>

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3 years ago

Which data type is variable 'a' as per below code?(numeric/non-numeric) Dim a as integer a=10 for grade 7 Computer

Lorico [155]

Answer:

The answer is "numeric".

Step-by-step explanation:

The Dim keyword is used in Visual Basic which is used to establish the dependent variable and other information such as the code that the variable may access the variables, computer utilizes the statement Dim. The dimensions are brief and then used to define variables. The Dim statement is placed just after sub definition only at the start of a VBA module (short for Subroutine).The variable to hold an integer value is seen in the above example.

8 0

3 years ago

The radius of the circle on a basketball court is 6 feet. What are the approximate

Leno4ka [110]

Answer:

C= 37.69ft

A= 113.09ft

Step-by-step explanation:

Circumference=

=37.69

Area=

Area = pi * 6 ^2

Area =113.09

3 0

3 years ago

Please help me with the worksheet

aivan3 [116]

Answer:

9) a = ¾, <u>vertex</u>: (-4, 2), <u>Equation</u>: y = ¾|x + 4| + 2

10) a = ¼, <u>vertex</u>: (0, -3), <u>Equation</u>: y = ¼|x - 0| - 3

11) a = -4, <u>vertex</u>: (3, 1), <u>Equation</u>: y = -4|x - 3| + 1

12) a = 1, <u>vertex</u>: (-2, -2), <u>Equation</u>: y = |x + 2| - 2

Step-by-step explanation:

I could <u><em>only</em></u> work on questions 9, 10, 11, 12 in accordance with Brainly's rules. Nevertheless, the techniques demonstrated in this post applies to all of the given problems in your worksheet.

<h2><u>Definitions:</u></h2>

The given set of graphs are examples of absolute value functions. The <u>general form</u> of absolute value functions is: y = a|x – h| + k, where:

|a| = determines the vertical stretch or compression factor (wideness or narrowness of the graph).

(h, k) = vertex of the function

x = h represents the axis of symmetry.

<h2><u>Solutions:</u></h2><h3>Question 9) ⇒ Vertex: (-4, 2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (0, 5) and substitute into the general form (equation):

y = a|x – h| + k

5 = a| 0 - (-4)| + 2

5 = a| 0 + 4 | + 2

5 = a|4| + 2

5 = 4a + 2

Subtract 2 from both sides:

5 - 2 = 4a + 2 - 2

3 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{3}{4}\:=\:\frac{4a}{4}}$

a = ¾

Therefore, given the value of a = ¾, and the vertex, (-4, 2), then the equation of the absolute value function is:

<u>Equation</u>: y = ¾|x + 4| + 2

<h3>Question 10) ⇒ Vertex: (0, -3)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -2) and substitute into the general form (equation):

y = a|x – h| + k

-2 = a|4 - 0| -3

-2 = a|4| - 3

-2 = 4a - 3

Add 3 to both sides:

-2 + 3 = 4a - 3 + 3

1 = 4a

Divide both sides by 4 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{1}{4}\:=\:\frac{4a}{4}}$

a = ¼

Therefore, given the value of a = ¼, and the vertex, (0, -3), then the equation of the absolute value function is:

<u>Equation</u>: y = ¼|x - 0| - 3

<h3>Question 11) ⇒ Vertex: (3, 1)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (4, -3) and substitute into the general form (equation):

y = a|x – h| + k

-3 = a|4 - 3| + 1

-3 = a|1| + 1

-3 = a + 1

Subtract 1 from both sides to isolate <em>a</em>:

-3 - 1 = a + 1 - 1

a = -4

Therefore, given the value of a = -4, and the vertex, (3, 1), then the equation of the absolute value function is:

<u>Equation</u>: y = -4|x - 3| + 1

<h3>Question 12) ⇒ Vertex: (-2, -2)</h3>

<u>Solve for a:</u>

In order to solve for the value of <em>a</em>, choose another point on the graph, (-4, 0) and substitute into the general form (equation):

y = a|x – h| + k

0 = a|-4 - (-2)| - 2

0 = a|-4 + 2| - 2

0 = a|-2| - 2

0 = 2a - 2

Add 2 to both sides:

0 + 2 = 2a - 2 + 2

2 = 2a

Divide both sides by 2 to solve for <em>a</em>:

$\LARGE\mathsf{\frac{2}{2}\:=\:\frac{2a}{2}}$

a = 1

Therefore, given the value of a = -1, and the vertex, (-2, -2), then the equation of the absolute value function is:

<u>Equation</u>: y = |x + 2| - 2

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2 years ago