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3 years ago

Help please ! It’s geometry

Mathematics

2 answers:

Leto [7]3 years ago

8 0

Answer:

x=15.56

y=15.56

Step-by-step explanation:

Scorpion4ik [409]3 years ago

4 0

Answer:

$x = 11 \sqrt{2}$

$y = 11 \sqrt{2}$

Step-by-step explanation:

$\sin(45) = \frac{y}{22} \\ \\ \frac{1}{ \sqrt{2} } = \frac{y}{22} \\ \\ y = \frac{22}{ \sqrt{2} } \\ \\ y = 11 \sqrt{2}$

$\cos(45) = \frac{x}{22} \\ \\ x = 11 \sqrt{2}$

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The sum of the measures of two complementary angles exceeds the difference of their measure by 86_. Find the measure of each ang

Bad White [126]

As the sum of two complementary angles = a + b = 90 degree -------(1)

Difference of two complementary angles = a – b

According to question;

The difference of two complementary angles exceed the sume (90) by 86.

a – b = 90 – 86 = 4 -------(2)

adding equation (1) and (2);

2a = 90 + 4 = 94

a = 94 / 2 = 47

putting a = 47 in equation (1);

47 + b = 90

b = 90 – 47 = 43

So angle a = 47 and angle b = 43

5 0

4 years ago

Solve for x in the equation x^2 + 2x+ 1 = 17.

muminat

Answer:

first, subtract 17 on both sides: x²+2x-16=0

this cannot be factored, so use the quadratic formula to solve for x:

b²-4ac=2²-4(10(-16)=4+64=68

√68=2√17

so x=(-2+2√17)/2 or x=(-2-2√17)/2

x=-1+√17 or x=-1-√17

Step-by-step explanation:

7 0

4 years ago

Prove that: (secA-cosec A) (1+cot A +tan A) =( sec^2A/cosecA)-(Cosec^2A/secA)

Ksju [112]

Step-by-step explanation:

$(\sec A - \csc A)(1 + \cot A + \tan A)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos A}{\sin A} + \dfrac{\sin A}{\cos A} \right)$

$=(\sec A - \csc A)\left(1 + \dfrac{\cos^2 A + \sin^2 A}{\sin A\cos A} \right)$

$=(\sec A - \csc A)\left(\dfrac{1 + \sin A \cos A}{\sin A \cos A} \right)$

$=\left(\dfrac{\frac{1}{\cos A} - \frac{1}{\sin A}+\sin A - \cos A}{\sin A\cos A}\right)$

$=\dfrac{\sin A - \sin A \cos^2A - \cos A + \cos A\sin^2A}{(\sin A\cos A)^2}$

$=\dfrac{\sin A(1 - \cos^2A) - \cos A (1 - \sin^2 A)}{(\sin A\cos A)^2}$

$=\dfrac{\sin^3A - \cos^3A}{\sin^2A\cos^2A}$

$=\dfrac{\sin A}{\cos^2A} - \dfrac{\cos A}{\sin^2A}$

$=\left(\dfrac{1}{\cos A}\right)\left(\dfrac{\sin A}{1}\right) - \left(\dfrac{1}{\sin^2A}\right) \left(\dfrac{\cos A}{1}\right)$

$=\sec^2A\csc A - \csc^2A\sec A$

5 0

3 years ago

16 + -3 - 5/7j - 6/7j + 4

Flura [38]

Answer:

17-11j/7

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Work out the size of angle X. X Х 33° 20° 165°

vitfil [10]

Answer:

142 degrees

Step-by-step explanation:

The sum of angle in a quadrilateral is 360 degrees

33 + 20 + 165 + X =360

53 + 165 + X = 360

218 + X = 360

X = 360 - 218

X = 142

Hence the size of angle X is 142 degrees

5 0

3 years ago