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ser-zykov [4K]
2 years ago
6

-8 - 1/3n ≤ - 25 Please show the equation and steps please

Mathematics
2 answers:
mojhsa [17]2 years ago
7 0
My answer is: n >_ 51

Explain:
=> Step 1: - 8 - 1/3 n <_ - 25 , After this we multi by 3
=> Step 2: - 24 - n <_ - 75 , we move constant sign to right hand side
=> Step 3: - n <_ - 75 + 24 , then we change the sign
=> Step 4: answer is: n >_ 51
sergey [27]2 years ago
3 0

Answer:
-8 - 1/3n ≤ - 25
solving-n E [51,+oo] , {n|n ≤ 51}
answer-n  ≤ 51

Step-by-step explanation:

I hope its help
Brainliest me pls
#CARRYONLEARNING

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Vera_Pavlovna [14]

Answer:

I'm not sure if that's what is meant cuz the text is a little ambiguous

Nevertheless, 62 people

Step-by-step explanation:

Amount = 2 + 4 + 8 + 16 + 32 =62 people

"Exponential Growth"

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asambeis [7]
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3 years ago
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The sum of two consecutive odd intergers is 32. Find the intergers.
elena-14-01-66 [18.8K]
So let the smaller integer be 2x+1 and the larger one be 2x+3. So 2x+1+2x+3 is 32. Simplifying, we get 4x+4=32. So subtracting 2 from both sides we get 4x+2=30. So dividing by 2 we get 2x+1=15. So 2x+3 is 17. So the numbers are 15 and 17
4 0
3 years ago
What is the area of the triangle?<br> 6<br> 2<br> 3
Llana [10]

Answer:

6

Step-by-step explanation:

Find the area of both triangles inside the bigger triangle and add them together.

Use the Pythagorean theorem to find the missing length of the leg in the smallest triangle:

a² + b² = c²

2² + b² = 3²

4 + b² = 9

5 = b²

2.2 ≈ b

Calculate the area of the smaller triangle:

1/2(bxh)

1/2(2 x 2.2)

1/2(4.4)

2.2

Calculate the area of the bigger triangle:

<em>We know that the longer leg is 3.8 units because we were able to subtract the length of the smaller triangle's leg from 6. </em>

1/2(bxh)

1/2(2 x 3.8)

1/2(7.6)

3.8

Add both areas to find the area of the largest triangle:

3.8 + 2.2 = 6

7 0
3 years ago
Expand the following:<br> a) x(x + 2)<br> b) x(2x - 5)<br> c) 2x(3x + 4)<br> d) 6x(x - 2)
TEA [102]

Answer:

<h2>a. \:  {x}^{2}  + 2</h2>

<h2> </h2><h2>b. \: 2 {x}^{2}  - 5x</h2><h2> </h2><h2>c. \: 6 {x}^{2}  + 8x</h2><h3> </h3><h3>d. \: 6 {x}^{2}  - 12x</h3>

solution,

a. \: x(x + 2) \\  \:  \:  = x \times x + 2 \times x \\  \:  \:  =  {x}^{2}  + 2x

b . \: x(2x - 5) \\  \:  = x \times 2x - x \times 5 \\  \:  \:  = 2 {x}^{2}  - 5x

c. \: 2x(3x + 4) \\  \:  = 2x \times 3x + 2x \times 4 \\  \:  \:  = 6 {x}^{2}  + 8x

d. \: 6x(x - 2) \\  \:  \:  = 6x \times x  - 6x \times 2 \\  \:  \:  = 6 {x}^{2}  - 12x

<h2> </h2><h2 />

Hope this helps...

Good luck on your assignment..

4 0
2 years ago
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