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3 years ago

5

Consider the formula for the average velocity, v, of a moving particle. In the formula, d1 and d2 represent the distance travele

d by the particle at times t1 and t2 respectively.

1 answer:

sergiy2304 [10]3 years ago

7 0

Take a better question d13 is the answer

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1. Simplify. 5–1(3–2)

konstantin123 [22]

Answer with explanation:

Using following law of indices

$1.x^a \times x^b=x^{a+b}\\\\2. (x^m)^n=x^{mn}\\\\ 3. x^{-n}=\frac{1}{x^n}\\\\4. \frac{x^m}{x^n}=x^{m-n}$

$1.5^{-1}\times 3^{-2}=\frac{1}{5}\times\frac{1}{3^2}\\\\=\frac{1}{5\times9}\\\\=\frac{1}{45}\\\\2. \frac{mn^{-4}}{p^0*q^{-2}}=\frac{mq^2}{n^4}\\\\ 3.0.0042=4.2\times 10^3\\\\4.6.12 \times 10^3=6.12 \times 1000=6120\\\\ 5.0.5 \times(8\times10^5})=\frac{1}{2}\times8 \times 10^5=4\times 10^5\\\\6. (9 \times 10^3)^2=9^2 \times (10^3)^2=81 \times 10^6\\\\7.( \frac{1}{2}a^{-4}\times b^2 )_{a=-2,b=4}{\text{or}}( \frac{1}{2}a^{4}\times b^{-2} )_{a=-2,b=4}=\frac{1}{2}\times (-2)^{-4}\times(4)^2{\text{or}}=\frac{1}{2}\times (-2)^{4}\times(4)^{-2}=\frac{16}{2\times16}=\frac{1}{2}$

$9. (4\times x\times y^2)^3\times (xy)^5=4^3\times x^3\times (y^2)^3\times x^5 \times y^5\\\\=64\times x^{3+5}\times y^{5+6}\\\\=64x^8y^{11}\\\\10.(2\times t^3)^3(0.4\times r)^2=2^3 \times (t^3)^3\times (0.4)^2 \times r^2=8\times t^9 \times 0.16 \times r^2=1.28r^2t^9$

8. A number raised to a negative exponent is negative.

Explaining with the help of few examples

$1.2^{-3}=\frac{1}{2^3}=\frac{1}{8}\\\\ 2.(-3)^{-3}=\frac{1}{(-3)^{3}}=\frac{-1}{27}$

Option C: Sometimes

1.Option B

2.Option A

3.Option C

4.Option A

5.Option D

6. $81 \times 10^6$

7.Option B

8.Option C

9.Option A

10.Option $1.28 r^2 \times t^9$

4 0

4 years ago

Read 2 more answers

Santa has many toys to deliver on Elm Street. If there are 48 kids that live on Elm

kobusy [5.1K]

Answer: 3 : 1

Step-by-step explanation:

We know that there are 48 kids in Elm street.

12 of them are boys, then the number of girls will be:

48 - 12 = 36

So there are 12 boys and 36 girls.

Then the ratio of girls to boys is 36:12

We can divide both numbers by the same number and we will get an equivalent ratio, if we divide by 12 in both sides, we have:

36/12 : 12/12

3 : 1

Then the ratio is 3 to 1.

7 0

3 years ago

If a certain number is increased by 5, one - half of the result is three - fifths of the excess of 61 over the number. Find the

Mariulka [41]

Answer:

fdvrjvbvjdvbjvnvxjvnfvrdcdjdcbf

Step-by-step explanation:

eejkncj jcewecwcwjcjk fewhb

6 0

3 years ago

PLEASE HELP AS SOON AS POSSIBLE

frutty [35]

Answer:

FALSE

TRUE

TRUE

Step-by-step explanation:

For median,

Arrange your numbers in numerical order.

Count how many numbers you have.

If you have an odd number, divide by 2 and round up to get the position of the median number.

If you have an even number, divide by 2. Go to the number in that position and average it with the number in the next higher position to get the median.

Source: https://www.verywellmind.com/how-to-identify-and-calculate-the-mean-median-or-mode-2795785

So for April median: 2.5, 3, 3.5, 3.5 (since we have 4 numbers we divide by 2 and we count by 2 places from left. Since we have even number data, we average 3 with the next higher position to get the median so (3+3.5)/2 = 3.25

For May apply same concept and you get median to be 2.25.

Median difference is 3.25-2.25 = 1

Therefore, statement 1 is false and statement 2 is true.

For average in May, add all numbers and divide by the number of data points so May= (2.5+3+3.5+3.5)/ 4 = 3.13

Apply same concept you for April and you get 2.38 as mean.

Mean difference is 3.13-2.38 = 0.75

Therefore, statement 3 is correct (true)

4 0

3 years ago

Solve each system by substitution <br><br> 4y - 6 = 2x<br> y- 3x=9

ArbitrLikvidat [17]

X = -3, y = 0 i think

6 0

4 years ago

Read 2 more answers