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diamong [38]
3 years ago
9

Solve the equation by factoring. 3x^2-5x-12=0

Mathematics
2 answers:
LUCKY_DIMON [66]3 years ago
7 0
Hope this helps you out! :)

timofeeve [1]3 years ago
3 0

Answer:

x = 3

x=-1\frac{1}{3} or x=-\frac{4}{3}

Step-by-step explanation:

3x² - 5x - 12 = 0

<u>Method 1:</u> <u>Factoring</u>

3x² + 4x - 9x - 12 = 0

(3x² + 4x) + (- 9x - 12) = 0

x(3x + 4) - 3(3x + 4) = 0

(x - 3)(3x + 4) = 0

<em>Two separate equations</em>

<u><em>x - 3 = 0</em></u>

<u><em>3x + 4 = 0</em></u>

x - 3 = 0

x - 3 + 3 = 0 + 3

3x + 4 = 0

3x + 4 - 4 = 0 - 4

3x = - 4

\frac{3x}{3} :-\frac{4}{3}

x=-1\frac{1}{3}

<u>Method 2:</u> <u>Quadratic Formula</u>

Ignore the A before the ±, it wouldn't let me type it correctly.

x=\frac{-b±\sqrt{b^{2} -4ac} }{2a}

3x² - 5x - 12 = 0

a = 3

b = - 5

c = - 12

x=\frac{-(-5)±\sqrt{(-5)^{2} -4((3)(-12))} }{2(3)}

x=\frac{-(-5)±\sqrt{25 -4((3)(-12))} }{2(3)}

x=\frac{-(-5)±\sqrt{25 +144} }{2(3)}

x=\frac{-(-5)±\sqrt{169} }{2(3)}

x=\frac{-(-5)±13}{2(3)}

x=\frac{5±13}{6}

<em>Two separate equations</em>

One must have a + (positive) and the other will have a - (negative).

x=\frac{5+13}{6}

x=\frac{18}{6}

x = 18 ÷ 6

x = 3

x=\frac{5-13}{6}

x=\frac{-8}{6}

x = - 8 ÷ 6

x=-1\frac{1}{3}

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