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slava [35]
3 years ago
10

Help please I don’t understand

Mathematics
2 answers:
Ksju [112]3 years ago
5 0

Answer:

Math

Step-by-step explanation:

Which one(s) did you want us to do? Answer in the comments of this questions and I'll help you from there

Zolol [24]3 years ago
4 0

Answer:

Hi

so all the whole numbers will be divided by one meaning it will look like

<u>3</u> x <u>9</u>

4 1

And

<u>8</u> x <u>5</u>

1 6

Etc, etc

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Transform the equation.
zvonat [6]

Answer:

2 (6/x-6)+4

Step-by-step explanation:

5 0
4 years ago
max read 1/8 of his book on Monday and 1/6 of his book on Tuesday. what fraction of his book did he read altogether on these day
miskamm [114]
1/8 + 1/6
= 1 x 3 + 1 x 4
——- ——
8 x 3 6 x 4

= 3/24 + 4/24
= 3 + 4
———-
24
= 7/24

8 0
3 years ago
A monomial of the 2nd degree with a leading coefficient of 3
iren2701 [21]

Answer: If the monomial has only one variable.

3x² is a monomial of the 2nd degree with a leading coefficient of 3.

Step-by-step explanation: Think of the your like terms such as the coefficents  A polynomial which has only one term is called monomial.

The degree of a monomial is defined as the sum of all the exponents of the variables.

A leading coefficient is the number multiply to the variable.

7 0
3 years ago
What is the greatest common factor of 48 and 80?
anyanavicka [17]

Answer:

16

Step-by-step explanation:

3 x 16 = 48

5 x16 = 80

3 0
4 years ago
Read 2 more answers
A bag contains 20 white marbles and 30 black marbles. if 7 marbles are chosen, what is the probability that there will be 2 whit
AlekseyPX
This is a hypergeometric distribution problem.
Population (N=50=W+B) is divided into two classes, W (W=20)  and B (B=30).
We calculate the probability of choosing w (w=2) white and b (b=5) black marbles.
Hypergeometric probability gives
P(W,B,w,b)=C(W,w)C(B,b)/(C(W+B,w+b)
where
C(n,r)=n!/(r!(n-r)!) the number of combinations of choosing r out of n objects.

Here
P(20,30,2,5)
=C(20,2)C(30,5)/(20+30, 2+5)
=190*142506/99884400
=0.2710

Alternatively, doing the combinatorics way:
#of ways to choose 2 from 20 =C(20,2)
#of ways to choose 5 from 30=C(30,5)
total #of ways = C(50,7)
P(20,30,2,5)=C(20,2)*C(30,5)/C(50,7)
=0.2710 
as before.
8 0
4 years ago
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