Jk=8x+6
J=(8x+6)/k
kL=6x+20
L=(6x+20)/k
JL=(8x+6)/k * (6x+20)/k
=(48x²+196x+120)/k²
Answer:
neither
Step-by-step explanation:
if you put those coordinates on a graph it would be curved and not be linear
Just did the work in class. It is greater than.
F(x) = 3ˣ + 10x and g(x) = 4x – 2, find (f-g)(x)
(f-g)(x) = f(x) - g(x):
(3ˣ + 10x) - (4x - 2) →→→ 3ˣ + 6x - 2. Then:
(f-g)(x) = 3ˣ + 6x - 2
Answer:
15.6
Step-by-step explanation:
