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ki77a [65]
2 years ago
14

A small tree was planted at a height of 17 feet. The tree has been planted for 12 months, and is now 66 feet tall. Which equatio

n could be used to find x, the average number of feet the tree grew each month?
Mathematics
1 answer:
artcher [175]2 years ago
6 0

Answer:

12x + 17 = 66

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❕What is the volume of the cone below? <br> •thanks to all who try to help out!
marta [7]

Volume of cone = 1/3 π r² h = 1/3 π (6)² (22) = 264π units³


Answer (A) : 264π units³

3 0
4 years ago
Read 2 more answers
How do I do this??????? 2/3x-(1/2x+1)<br>btw need it simplified
Setler79 [48]

Answer:

  1/6x -1

Step-by-step explanation:

"Simplify" generally means, "eliminate parentheses and combine like terms." In general, parentheses are eliminated by making use of the distributive property.

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  \dfrac{2}{3}x-\left(\dfrac{1}{2}x+1\right)=\dfrac{2}{3}x-\dfrac{1}{2}x-1=\left(\dfrac{2}{3}-\dfrac{1}{2}\right)x-1\\\\=\left(\dfrac{4}{6}-\dfrac{3}{6}\right)x-1=\boxed{\dfrac{1}{6}x-1}

5 0
2 years ago
Evaluate each expression if a = 6, b = 3, and c = 2.
cricket20 [7]

Answer:

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7 0
4 years ago
A deck of ordinary cards is shuffled and 13 cards are dealt. What is the probability that the last card dealt is an ace?
alexandr1967 [171]

Answer:

The probability that the last card dealt is an ace is \frac{1}{13}.

Step-by-step explanation:

Given : A deck of ordinary cards is shuffled and 13 cards are dealt.

To find : What is the probability that the last card dealt is an ace?

Solution :

There are total 52 cards.

The total arrangement of cards is 52!.

There is 4 ace cards in total.

Arrangement for containing ace as the 13th card is 4\times 51!.

The probability that the last card dealt is an ace is

P=\frac{4\times 51!}{52!}

P=\frac{4\times 51!}{52\times 51!}

P=\frac{4}{52}

P=\frac{1}{13}

Therefore, the probability that the last card dealt is an ace is \frac{1}{13}.

4 0
3 years ago
Solve it by substitution method:- 5x - 6y=-9 and 3x + 4y= 25
user100 [1]
\left\{\begin{array}{ccc}-5x-6y=-9&/\cdot2\\3x+4y=25&/\cdot3\end{array}\right\\+\left\{\begin{array}{ccc}-10x-12y=-18\\9x+12y=75\end{array}\right\\------------\\.\ \ \ \ \ \ \ -x=57\\.\ \ \ \ \ \ \ \ \ x=-57\\\\3\cdot(-57)+4y=25\\-171+4y=25\\4y=25+171\\4y=196\ \ \ \ /:4\\y=49\\\\Solution:x=-57;\ y=49.
8 0
4 years ago
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