Answer:
It would be less than 0.05.
Step-by-step explanation:
The hypothesis test was done to claim that the weight of participants has changed.
The null and alternative hypothesis could be written as:

being μ the population mean change in weight.
With that information, we can tell that is a two tailed test. Sample means that fall in any of the tails, with a z-statistic over 1.96 or under -1.96 (at a significance level of 0.05), will be evidence to reject the null hypothesis.
The information we have about the sample is the 95% confidence interval calculated from the sample information.
This confidence interval does not include the value μ=0.
Then, there is 2.5% of probabiltity that the population mean is under 2.177, the lower bound of the interval, which includes the value μ=0.
With this information, we can conclude that the P-value have to be under 0.05.