I mean I got 5/12 as my simplified answer but I might be wrong. I hope this helps in some way and sorry if I'm wrong
The numbers are 105 and 50
<em><u>Solution:</u></em>
Let "x" be the first number
Let "y' be the second number
Twice a number plus twice a second number is 310
Therefore,
twice of x + twice of y = 310
2x + 2y = 310 ---------- eqn 1
The difference between the numbers is 55
x - y = 55 -------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 2,
x = 55 + y ------ eqn 3
<em><u>Substitute eqn 3 in eqn 1</u></em>
2(55 + y) + 2y = 310
110 + 2y + 2y = 310
4y = 310 - 110
4y = 200
<h3>y = 50</h3>
<em><u>Substitute y = 50 in eqn 3</u></em>
x = 55 + 50
<h3>x = 105</h3>
Thus the numbers are 105 and 50
Answer:
That is very confusing!
Step-by-step explanation:
Answer:
C
Step-by-step explanation:
5x+15+2=5x+17
2 Simplify 5x+15+25x+15+2 to 5x+175x+17.
5x+17=5x+17
5x+17=5x+17
3 Since both sides equal, there are infinitely many solutions.
Infinitely Many Solutions
Pemdas
multiplication first
3 times 2=6
8 times 1=8
now we have
11+5+6+8
add
11+5=16
6+8=14
16+14=30
answer is 30