Question

(3x²+3x+5)+(7x²-9x=8)=10x²-12x=13

Answer 1

The value of x is equal to -5/6

To solve this question, we have to add two polynomials together. The polynomials are;

• $3x^2+3x+5$
• $7x^2-9x=8$

Addition of Polynomials

This involves adding of two or more different polynomials together. The polynomials adding together are or must be of the same degree. i.e x^2 must add to another coefficient of x^2 and x^3 adds to another coefficient of x^3 and so on.

In this given question, let's add the polynomials together.

$(3x^2+3x+5) + (7x^2-9x = 8\)\\3x^2 + 7x^2 + 3x-9x+5-8 =10x^2-6x-3$

Now, let's equate this with the last polynomial given

$10x^2-6x-3=10x^2-12x-13\\10x^2-10x^2-6x+12x-3+13\\0+12x+10\\12x=-10$

Let's solve for x

$12x=-10\\x=-\frac{10}{12}\\x = -\frac{5}{6}$

The value of x is equal to -5/6

Learn more on addition of polynomials here;

brainly.com/question/4142886