Choose the polynomial written in standard form.

The box plots show the weights, in pounds, of the dogs in two different animal shelters.

zimovet [89]

*see attachment below for the box plots that is being referred to

Answer:

*The median weight for shelter A is greater than that for shelter B

*The data for shelter B are a symmetric data set

Step-by-step explanation:

Let's take each stated option and examine the box plot to see which is TRUE or NOT.

OPTION 1: "The median weight for shelter A is greater than that for shelter B."

The median for shelter A = 21,

Median for shelter B = 18

Median weight for shelter A (21) is greater than that for shelter B.

This statement in this option is TRUE.

OPTION 2: "The median weight for shelter B is greater than that for shelter A."

Median for B (18) < median of A (21)

This statement in option is NOT TRUE.

OPTION 3: "The data for shelter A are a symmetric data set."

This is NOT TRUE because the length of both whiskers are unequal and also, the box is not divided equally. One side is longer than the other.

OPTION 4: "The data for shelter B are a symmetric data set."

This is TRUE because the length of both whiskers are relatively equal, and also, the rectangular box is divided equally.

OPTION 5: "The interquartile range for shelter A is 8"

This is NOT TRUE.

IQR = Q3-Q1

IQR for shelter A is approximately = 28-17 = 11

5 0

3 years ago

Fernando and Roger are both in an art class. Fernando has created 40 projects in class this year. Fernando has created five time

Natali [406]

40x5= 200 I'm not sure who created five times more projects than the other, but whoever did, created 200 projects.

3 0

3 years ago

Consider the following hypothesis test: H0: LaTeX: \mu_1-\mu_2=0μ 1 − μ 2 = 0 Ha: LaTeX: \mu_1-\mu_2\ne0μ 1 − μ 2 ≠ 0 The follow

Pavel [41]

Answer:

$z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53$

Step-by-step explanation:

Data given and notation

$\bar X_{1}=104$ represent the mean for the sample 1

$\bar X_{2}=106$ represent the mean for the sample 2

$\sigma_{1} =8.4$ represent the population standard deviation for the sample 1

$\sigma_{2}=7.6$ represent the population standard deviation for the sample 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:

H0: $\mu_{1}-\mu_{2} =0$

H1: $\mu_{1} -\mu_{2} \neq 0$

If we analyze the size for the samples both are greater than 30 and we know the population deviations so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

First we need to calculate the mean and deviation for each sample, after apply the formulas (2) and (3) we got the following results:

And with this we can replace in formula (1) like this:

$z=\frac{104-\bar 106}{\sqrt{\frac{8.4^2}{80}+\frac{7.6^2}{70}}}}=-1.53$

7 0

3 years ago

Explain how comparan

Umnica [9.8K]

How to comparan? Not sure

5 0

3 years ago

Read 2 more answers

To compare the production techniques used by foreign and local firms in Brazil, a random sample of 80 foreign firms and a random

alina1380 [7]

Answer:

An independent sample.

Step-by-step explanation:

In this scenario, to compare the production techniques used by foreign and local firms in Brazil, a random sample of 80 foreign firms and a random sample of 80 local firms are selected. We can safely conclude that this study uses an independent sample design.

An independent sample design can be defined as a research method that usually involves the use of multiple experimental groups (two or more). The samples or participants are only in one group and as such each group has no relationship with the other. This simply means that, the samples in a particular group is having no relationship with the other samples in another group.

Ultimately this implies, each samples are independent and satisfies only one condition of the independent sample design during the experiment to compare the production technique used by foreign and local firms in Brazil.

<em>Hence, the researcher would use only two variables or conditions: a random sample of 80 foreign firms and a random sample of 80 local firms are selected.</em>

6 0

2 years ago