<span>o,t,t,f,f,s,S,E,N,T,E,T </span>
<span>It's the first letter of all the numbers starting with one, two, three, four,... </span>
<span>The second pattern I might guess would be move the O back two spaces then move one space back, then repeat. </span>
<span>JKLMNO, JKLOMN, JKOLMN, OJKLMN, JKLMON, JKOLMN, ... </span>
<span>The second one I'm not sure about because there are only three starting terms to work with. It's hard to see the real pattern with that little to work with. </span>
<span>Hope this helps. </span>
Answer:
--- Radius
--- Height
Explanation:
Given
Object: Can (Cylinder)

Required
Maximize the volume
The surface area is:

Substitute 517.8 for S.A

Divide through by 2

Factorize:

Divide through by 

Make h the subject
--- (1)
Volume (V) is calculated as:

Substitute (1) for h

Open Bracket

Differentiate V

Set V' to 0

Collect Like Terms

Divide through by 3

Divide through by 



Take square root of both sides


Recall that:

Substitute 5.24 for r





Hence, the dimension that maximize the volume is:
--- Radius
--- Height
The figure is not marked in any way that would indicate it is a parallelogram. If we assume it is, then
... BE = DE
... 10x -3 = 8x -1 . . substitute the given expressions
... 2x = 2 . . . . . . . . add 3-8x
... x = 1 . . . . . . . . . . divide by 2
The appropriate choice is ...
... A. 1 unit
_____
Since the figure is not marked to indicate BE=DE, you could argue that any answer is correct.