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yaroslaw [1]
2 years ago
7

Two grapefruits and three oranges cost $1.95. Three grapefruits and two oranges cost $2.05.

Mathematics
1 answer:
geniusboy [140]2 years ago
4 0

Answer:

  • one orange costs $0.35  and  one grapefruit costs $0.45

Step-by-step explanation:

<em>let grapefruits be g , let oranges be o</em>

so first equation:

→2g + 3o  = $1.95

→g = ($1.95 - 3o)/2

so second equation:

→ 3g + 2o = $2.05

→ g = ($2.05 - 2o)/3

Solving simultaneously:

→ ($2.05 - 2o)/3 = ($1.95 - 3o)/2

→ 2($2.05 - 2o) = 3($1.95 - 3o)

→ 4.1 - 4o = 5.85 - 9o

→ - 4o + 9o = 5.85 - 4.1

→ 5o = 1.75

→ o = $0.35

Therefore one orange costs $0.35

Then one grapefruit costs g → ($1.95 - 3o)/2

                                               → g = ($1.95 - 3(0.35))/2

                                               → g = 0.45

Therefore one grapefruit costs $0.45

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Consider the following probability distribution function of the random variable X which represents the number of people in a gro
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Answer:

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(b) 3.45 and 1.86

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(d) 0.016

Step-by-step explanation:

The random variable <em>X</em> denotes the number of people in a group (party) at a restaurant.

(a)

The formula to compute the mean is:

\mu=\sum {x\cdot P(X=x)}

Consider the Excel sheet attached.

The mean is, 3.55.

(b)

The formula to compute the variance is:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}

Consider the Excel sheet attached.

Compute the variance as follows:

\sigma^{2}=[\sum {x^{2}\cdot P(X=x)}]-(\mu)^{2}\\\\=16.05-(3.55)^{2}\\\\=3.4475\\\\\approx 3.45

The variance is, 3.45.

Compute the standard deviation as follows:

\sigma=\sqrt{\sigma^{2}}\\\\=\sqrt{3.45}\\\\=1.85742\\\\\approx 1.86

The standard deviation is, 1.86.

(c)

Compute the probability that the next party will be over 4 people as follows:

P(X>4)=P(X=5)+P(X=6)+P(X=7)+P(X=8)\\\\=0.10+0.05+0.05+0.05\\\\=0.25

Thus, the probability that the next party will be over 4 people is 0.25.

(d)

Compute the probability that the next three parties will each be over 4 people as follows:

It is provided that the three parties are independent.

P (Next 3 parties will be each over 4) = [P (X > 4)]³

                                                           =(0.25)^{3}\\=0.015625\\\approx 0.016

Thus, the probability that the next three parties will each be over 4 people is 0.016.

3 0
3 years ago
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