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xxMikexx [17]
3 years ago
5

HELP MEE PLEASE! PLEASE DONT MESS AROUND!​

Mathematics
1 answer:
Luden [163]3 years ago
5 0

Answer:

its rotation

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Stefanie is painting her bedroom. She can paint 12 2/3 square feet in 2/5 of an hour. How many square feet can she paint in one
aalyn [17]

Answer:

31\frac{2}{3}

Step-by-step explanation:

since its only 2/5 of 1 hour, two 2/5 equal 4/5 so we divide the 12 2/3 by 2 to find the 1/5 which is 6 1/3

12\frac{2}{3}÷2=6\frac{1}{3}

12\frac{2}{3} +12\frac{2}{3}=25\frac{1}{3}

12\frac{1}{3} +6\frac{1}{3}=31\frac{2}{3}

4 0
3 years ago
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Does anyone know how to calculate this
stich3 [128]

Answer:

no not me sorry I wish I could help.

5 0
3 years ago
108 centimeters equal how many meters?
Sveta_85 [38]

Answer:

1.08 meters

Step-by-step explanation:

Divide by 100 to find this out. 108/100 = 1.08

You can remember this by knowing that the "centi-" prefix means 100 (technically, 100ths). Just like you probably already know 100 cents in a dollar (USD) or 100 years in a century. Even the "cent" in percent means per hundred. There are 100 centimeters in a meter. A centimeter is about as wide as your little finger. A meter is close to a yard.

7 0
2 years ago
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Pine Bluff Middle School is having its annual Spring Fling dance, which will cost
Anon25 [30]
I think your asking  how much the school will have left over. If so:

125 ( not including the tickets)
It depends on how many kids are coming to the dance in order to fully solve this problem.

You didn't word this properly so that what I got with what I had:)

If you have anymore questions, ask me them on my profile so I'll be sure to get them:)

I hope this helps:)
3 0
3 years ago
Item 7
Mariulka [41]

Answer:

A = 74.7^\circ

B = 42.5^\circ

C = 62.8^\circ

Step-by-step explanation:

Given

A = (-1,2) \to (x_1,y_1)

B = (2,8) \to (x_2,y_2)

C = (4,1) \to (x_3,y_3)

Required

The measure of each angle

First, we calculate the length of the three sides of the triangle.

This is calculated using distance formula

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

For AB

A = (-1,2) \to (x_1,y_1)

B = (2,8) \to (x_2,y_2)

d = \sqrt{(-1 - 2)^2 + (2 - 8)^2

d = \sqrt{(-3)^2 + (-6)^2

d = \sqrt{45

So:

AB = \sqrt{45

For BC

B = (2,8) \to (x_2,y_2)

C = (4,1) \to (x_3,y_3)

BC = \sqrt{(2 - 4)^2 + (8 - 1)^2

BC = \sqrt{(-2)^2 + (7)^2

BC = \sqrt{53

For AC

A = (-1,2) \to (x_1,y_1)

C = (4,1) \to (x_3,y_3)

AC = \sqrt{(-1 - 4)^2 + (2 - 1)^2

AC = \sqrt{(-5)^2 + (1)^2

AC = \sqrt{26

So, we have:

AB = \sqrt{45

BC = \sqrt{53

AC = \sqrt{26

By representation

AB \to c

BC \to a

AC \to b

So, we have:

a = \sqrt{53

b = \sqrt{26

c = \sqrt{45

By cosine laws, the angles are calculated using:

a^2 = b^2 + c^2 -2bc \cos A

b^2 = a^2 + c^2 -2ac \cos B

c^2 = a^2 + b^2 -2ab\ cos C

a^2 = b^2 + c^2 -2bc \cos A

(\sqrt{53})^2 = (\sqrt{26})^2 +(\sqrt{45})^2 - 2 * (\sqrt{26}) +(\sqrt{45}) * \cos A

53 = 26 +45 - 2 * 34.21 * \cos A

53 = 26 +45 - 68.42 * \cos A

Collect like terms

53 - 26 -45 = - 68.42 * \cos A

-18 = - 68.42 * \cos A

Solve for \cos A

\cos A =\frac{-18}{-68.42}

\cos A =0.2631

Take arc cos of both sides

A =\cos^{-1}(0.2631)

A = 74.7^\circ

b^2 = a^2 + c^2 -2ac \cos B

(\sqrt{26})^2 = (\sqrt{53})^2 +(\sqrt{45})^2 - 2 * (\sqrt{53}) +(\sqrt{45}) * \cos B

26 = 53 +45 -97.67 * \cos B

Collect like terms

26 - 53 -45= -97.67 * \cos B

-72= -97.67 * \cos B

Solve for \cos B

\cos B = \frac{-72}{-97.67}

\cos B = 0.7372

Take arc cos of both sides

B = \cos^{-1}(0.7372)

B = 42.5^\circ

For the third angle, we use:

A + B + C = 180 --- angles in a triangle

Make C the subject

C = 180 - A -B

C = 180 - 74.7 -42.5

C = 62.8^\circ

8 0
2 years ago
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