Since secant is the inverse of cosine function, when the cosine function has a 'zero' the secant will have a vertical asymptote.
Graphing a cosine with a right shift of pi, the zeros would be at pi and 2pi.
This will make the vertical asymptotes of the secant function be at pi and 2pi.
I hope you understand.
Answer:
<h2>The vessel in distress is located in between vessels A and B</h2>
Step-by-step explanation:
To describe how we arrive at the answer, we are going to use the drawing i have attached to this response.
southwest of ship A is just a distance around the third quadrant (using the cardinal point) and it is below A
North of B is few distances ahead of ship B.
<em>Please see the attached sketch </em>
Answer:
(x-4)²/16 + (y-8)²/25 = 1
Step-by-step explanation:
center (h,k): ((4+4)/2 , (3+13)/2) = (4 , 8)
a = 13-8 = 5 c = 8-5 = 3
b = √5²-3² = 4
Equation: (x-h)²/b² + (y-k)²/a² = 1
(x-4)²/16 + (y-8)²/25 = 1
Answer:
I. x + y = -3 --> y = -x - 3
II. y = 2x
2x = -x - 3
3x = - 3
x = -1
y = 2*(-1) = -2