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Nady [450]
3 years ago
14

If m∠JKP=3r+12 and m∠2=4r−2, what is ∠JKN?

Mathematics
1 answer:
Leokris [45]3 years ago
8 0
The answer seems to be 108
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Is 5/10 and 8/18 proportional
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5/10 = 1/2

8/18 = 4/9

1/2 > 4/9

They're not proportional.
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A cruise ship travels 20 miles in 50 minutes. How far does it travel in one minute?​
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Step-by-step explanation:

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In the data set shown below, what is the value of the quartiles? {42, 43, 44, 44, 48, 49, 50} A. Q1 = 43.5; Q2 = 44; Q3 = 49 B.
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C

Step-by-step explanation:

I don't actually know how to explain it but,

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Anitais making curtain to surround a table.she bought 3/1/4 yards of fabric ,her total was $13, what was the cost per yard
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Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f
castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean (\mu) = 115 \times 20

= 2300

Standard deviation = 20 \times \sqrt{115}

Standard deviation (SD) = 214.4761

TO find:

a) P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})

P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})

P(x > 3500)= P(Z > \dfrac{1200}{214.4761})

P(x > 3500)= P(Z >5.595)

From the Z-table, since 5.595 is > 3.999

P(x > 3500)=1-0.9999

P(x > 3500) = 0.0001

b)

Here, the replacement time for the mean (\mu) = \dfrac{0+0.5}{2}

= 0.25

Replacement time for the Standard deviation \sigma = \dfrac{0.5-0}{\sqrt{12}}

\sigma = 0.1443

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = \sqrt{(115\times 20^2) +(114\times (0.1443)^2)}

= \sqrt{(115\times 400) +(114\times 0.02082249}

= \sqrt{(46000) +2.37376386}

= \sqrt{(46000) +(2.37376386)}

= \sqrt{46002.374}

= 214.482

Now; the required probability:

P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})

P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})

P(x > 4125) = P(Z >8.376)

P(x > 4125) =1-  P(Z

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0
3 years ago
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