Will someone help me with this problem please.

Consider the function represented by the equation 6q = 3s - 9. Write the equation in function notation, where q is the independe

serg [7]

Answer:

s = 2q + 3

Step-by-step explanation:

A linear function has the form:

● y = mx + b

● y is the output of the function

● x is the variabke that we input

● b is the y-intetcept.

Focus on y and x.

Notice that y depends of the value of x. The value of y changes by changing x. So the value of x controls the output y.

y is dependent but x is not.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● 6q = 3s - 9

We want q to be the independent variable wich means that q will be the input. Therefore s should be the output.

The strategy we are going to follow is separating s in one side alone.

● 6q = 3s - 9

Add 9 to both sides

● 6q + 9 = 3s -9 + 9

● 6q + 9 = 3s

Divide both sides by 3

● (6q + 9)/3 = (3s)/3

● (6q)/3 + 9/3 = s

● s = 2q + 3

So the answer is s = 2q + 3

6 0

3 years ago

A sporting goods store sold 2.5 times as many footballs as basketballs last year. Which statement is true? The ratio of football

Mrac [35]

Footballs : basketballs = 2.5 : 1
(x 2)
footballs : basketballs = 5 : 2
⇒ basketballs : footballs = 2 : 5

Answer: <span>The ratio of basketballs to footballs is 5 : 2.</span>

7 0

3 years ago

Find the probability of atleast three successes in six trials of a binomial experiment in which the probability of success is 50

yan [13]

The binomial cumulative probability with p=0.5 for 3+ successes is as follows:

$P(3+)=\sum_{k=3}^6 {{6}\choose{k}}p^k(1-p)^{6-k}$

for p=0.5 (50% success rate) it becomes:

$P(3+)=\sum_{k=3}^6 {{6}\choose{k}}0.5^6=\frac{21}{32}=0.65625$

the probability is 0.65625, or about 66%

7 0

3 years ago

The rate of 225 mi in 7 hr written as a unit rate

mel-nik [20]

Answer:

32.14 an hour

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz. An ornithologi

il63 [147K]

Answer:

The formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1 - 0.7}{2} = 0.15$

Now, we have to find z in the Z-table as such z has a p-value of $1 - \alpha$ .

That is z with a pvalue of $1 - 0.15 = 0.85$ , so Z = 1.037.

Now, find the margin of error M as such

$M = z\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

Assume that body masses of Goldfinch birds follow a normal distribution with standard deviation equal to 0.04 oz.

This means that $\sigma = 0.04$ .

Sample of 10 birds:

This means that $n = 10$ .

The margin of error is of:

$M = z\frac{\sigma}{\sqrt{n}}$

$M = 1.037\frac{0.04}{\sqrt{10}}$

$M = 0.013$

The lower end of the interval is the sample mean of $\overline{x}$ subtracted by M.

The upper end of the interval is the sample mean of $\overline{x}$ added to M.

Then, the formula to generate 70% confidence interval is: $[\overline{x} - 0.013, \overline{x} + 0.013]$ , in which $\overline{x}$ is the sample mean.

8 0

3 years ago