x + 47 = 92. <--- x represents the number of 3rd graders
x +47-47 = 92-47
x=45
There are 45 third grader. Hope this helped!
Problem 1:
1) 3/5x-1 x 3/4=9/10
3x/5-1 x 3/4=9/10
2) 3x/5-1 x 3/4=9/10
3x/5-3/4=9/10
3) 3x/5-3/4=9/10
+3/4 +3/4
4) 3x/5=33/20
5) 5 x 3x/5= 5 x (33/20)
6) 3x=33/4
7) 3x=33/4
/3 /3
8) x=11/4
Problem 2:
1) 6/7+2/5x=-4/5
6/7+2x/5=-4/5
2) 6/7+2x/5=-4/5
-6/7 -6/7
3) 2x/5= --58/35
4) 5 x 2x/5= 5 x (--58/35)
5) 2x= --58/7
6) 2x= --58/7
/2 /2
x= --29/7
Answer:
x=1/3 or x=−2
if i can be brainliest that would be great
Step-by-step explanation:
Step 1: Add 2 to both sides.
3x^2+5x−2+2=0+2
3x^2+5x=2
Step 2: Since the coefficient of 3x^2 is 3, divide both sides by 3.
3x^2+5x/3=2/3
x^2+5/3x=2/3
Step 3: The coefficient of 5/3x is 5/3. Let b=5/3.
Then we need to add (b/2)^2=25/36 to both sides to complete the square.
Add 25/36 to both sides.
x^2+5/3x+25/36=2/3+25/36
x^2+5/3x+25/36=49/36
Step 4: Factor left side.
(x+5/6)^2=49/36
Step 5: Take square root.
x+5/6=±√49/36
Step 6: Add (-5)/6 to both sides.
x+5/6+ −5/6=
−5/6±√49/36x=−5/6±√49/36x=
1/3 or x=−2
Answer:
There are only 6 numbers that fit that description. (4,12,24,32,44,52)
Answer:
See attachment for cube
Step-by-step explanation:
Given
Required
The net of the cuboid
A cuboid has 6 faces.
The dimension of these faces are:
Length and Width; Length and Height;
Length and Width; Length and Height;
Width and Height; Width and Height;
This means that the faces will have the following dimensions:
6cm by 3cm; 6cm by 2cm
6cm by 3cm; 6cm by 2cm
3cm by 2cm; 3cm by 2 cm
Taking into account the above measurements and dimensions, you draw 6 faces, then join similar sides lengths.
<em>See attachment for net of the cuboid</em>
