the data represents the heights of fourteen basketball players, in inches. 69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 8
Daniel [21]
If you would like to know the interquartile range of the new set and the interquartile range of the original set, you can do this using the following steps:
<span>The interquartile range is the difference between the third and the first quartiles.
The original set: </span>69, 70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77, 82
Lower quartile: 72
Upper quartile: 76.25
Interquartile range: upper quartile - lower quartile = 76.25 - 72 = <span>4.25
</span>
The new set: <span>70, 72, 72, 74, 74, 74, 75, 76, 76, 76, 77, 77
</span>Lower quartile: 72.5
Upper quartile: 76
Interquartile range: upper quartile - lower quartile = 76 - 72.5 = 3.5
The correct result would be: T<span>he interquartile range of the new set would be 3.5. The interquartile range of the original set would be more than the new set.</span>
Answer:
I think (D)
Step-by-step explanation:
X= -7 y=2 (-7,2).
You multiply the first equation by 2 and the second by 3, then you can cancel out the x values to get the y value. Then you go back and plug in the y value to get x.
The answer is 3 + √5 and 3 - √5.
This is quadratic equation: x²
- 6x +
4 = 0
The general quadratic equation is ax² +
bx +
c = 0
Our equation can be rewritten: 1x² + (-6)x + 4 = 0
So, in our equation we have: a = 1, b = -6, c = 4
Now, x can be calculated using the formula:
From here:
Ok so what you need to do is first find the area of the circle using π r^2. So π12^2 or π144= 452.389342117 This is the area of the whole circle. To find the area of the sector you have to multiply the total area by 172/360 or 0.47777777777 This will get you 216.141574567 round as necessary but your answer is <span>216.141574567units^2</span>
