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2 years ago

The swim team members each swam less than 55 yards as a warm up Saturday morning.

Mathematics

1 answer:

Nana76 [90]2 years ago

8 0

Answer:Whats the prompt so I know what to do?

Step-by-step explanation:

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9. Which of the following relations is a function?

elena-14-01-66 [18.8K]

The answer is D because the first number doesn’t reapeat

5 0

3 years ago

Find the area of the trapezoid

Alexandra [31]

Answer:

$\sf area \ of \ trapezoid \ =375 \ mm^2$

Explanation:

$\sf area \ of \ trapezoid \ = \dfrac{1}{2} * ( base \ 1 + base \ 2 ) * height$

using the formula:

$\sf area \ of \ trapezoid \ = \dfrac{1}{2} * ( 14+ 36 ) * 15$

$\sf area \ of \ trapezoid \ = \dfrac{1}{2} * ( 50 ) * 15$

$\sf area \ of \ trapezoid \ =25 * 15$

$\sf area \ of \ trapezoid \ =375 \ mm^2$

5 0

2 years ago

Read 2 more answers

A semicircle is attached to the side of a rectangle as shown.

laiz [17]

Answer:

$58.8\ mm^2$

Step-by-step explanation:

we know that

The area of the figure is equal to the area of rectangle plus the area of semicircle

step 1

Find the area of rectangle

The area of rectangle is equal to

$A=bh$

where

$b=9\ mm\\h=3\ mm$

substitute

$A=(9)(3)=27\ mm^2$

step 2

Find the area of semicircle

The area of semicircle is equal to

$A=\frac{1}{2}\pi r^{2}$

we have

$r=9/2=4.5\ mm$ ---> the radius is half the diameter

$\pi =3.14$

substitute

$A=\frac{1}{2}(3.14) (4.5)^{2}$

$A=31.8\ mm^2$

step 3

Find the area of the figure

$A=27+31.8=58.8\ mm^2$

4 0

3 years ago

Read 2 more answers

Find the value of d

tamaranim1 [39]

C : B = D : E
6 : 5 = D : 3
D = 3.6

4 0

3 years ago

Please help! Find m<1 A. 147 B. 123 C. 90 D. 57

sergiy2304 [10]

I hope this helps you

1+33+57=180

1+90=180

1= 90

3 0

3 years ago

Read 2 more answers