Question

Write the equation of the line that includes the point (1,5) and has a slope of 3 in standard form.

Answer 1

Answer:

-3x + y = 2

Step-by-step explanation:

The slope is 3. So the coefficient of x is 3.

when x = 1, y = 5.

So 3*1 + c = 5

So c is 2.

So y = 3x + 2

Therefore, taking 3x to the LHS, we get,

-3x + y = 2

Hope it helps ;)

Answer 2

For this case we have that the equation of the point-slope form is given by:

$(y-y_ {0}) = m (x-x_ {0})$

Where:

m: It's the slope

$(x_ {0}, y_{0})$: It is a point through which the line passes

We have to:

$(x_ {0}, y_{0}) = (1,5)\\m = 3$

Then, the equation is:

$y-5 = 3 (x-1)\\y-5 = 3x-3\\-5 + 3 = 3x-y\\-2 = 3x-y$

We multiply by "-" on both sides of the equation:

$-3x + y = 2$

Answer:

Option B