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Slav-nsk [51]
3 years ago
12

Find the area. help pls

Mathematics
1 answer:
lions [1.4K]3 years ago
6 0

Answer:

81.6 inches squared

Step-by-step explanation:

The formula for calculating all parallelograms is Area+=base*height.

The height is given to you, 6.8, the base of the figure is also given, 12.

Now all you have to do is to multiply.

That would get you to 81.6.

(When asked for area of parallelogram, the length of any line other than the height and base is not needed)

hoped this helped!

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12) The school that Danielle goes to is selling tickets to a choral performance. On the first day of
kicyunya [14]

Answer:

Senior citizen tickets = $9

Student tickets = $11

Step-by-step explanation:

We begin by converting these into simultaneous linear equation;

Senior citizen tickets = a

Student tickets = b

5a + 9b = 144

14a + 6b = 192

5a = 144 - 9b

a = 144/5 - 9b/5

a = 28.8 - 1.8b

We now substitute this into the first equation

14(28.8 - 1.8b) + 6b = 192

403.2 - 25.2b +6b = 192

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b = -211.2/-19.2

b = 11

Put the value of b into either equation

5a + 9b = 144

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5a +99 = 144

5a = 144-99

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6 0
3 years ago
jason and his family travels 160 miles in 3.2 hours. if they continue at this constant speed, how long will it take them to trav
Misha Larkins [42]
Set up a proportion 
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cross multiply and solve for x and you get x≈6
It will take them 6 hours

3 0
4 years ago
Which is a unit rate ? 4 dollars to 3 cans 5 students to 2 teachers 6 hours and 1 book 3 miles 2 days
9966 [12]
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6 0
3 years ago
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How do I solve this problem. I have to find the missing side lengths and lease my sender as radicals in simplest form
nlexa [21]

Answer:

x = y = 2√2

Step-by-step explanation:

Find the diagram attached

To get the unknown side x and y, we need to use the SOH CAH TOA identity

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Hypotenuse = 4

Sin theta = opposite/hypotenuse

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x = 4 sin 45

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x = 4 * 1/√2 * √2/√2

x = 4 * √2/√4

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x = 2√2

Similarly;

cos theta = adjacent/hypotenuse

cos 45 = y/4

y = 4cos45

y = 4 * 1/√2

y = 4 * 1/√2 * √2/√2

y = 4 * √2/√4

y = 4 * √2/2

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3 years ago
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