This is the difference of two perfect cubes.
(6y-4)(36y^2+24y+16)
Solve for x then replace x with f⁻¹(x) and y with x
y=(4^x-5)/3
times 3
3y=(4^x-5)
add 5
3y+5=4^x
take log₄ both sides
log₄(3y+5)=x
switch
f⁻¹(x)=log₄(3y+5)
Answer:
Yes, I am find the like you
Answer:
x=9
Step-by-step explanation:
Answer:
I would try to help you but i dropped out in the 2nd grade back in 86 so you messed up sir
Step-by-step explanation: